我在
JSONModel library读JSON时遇到问题
{"images":[{"id":1,"name":"name1","img":"3423","note":"note1"},{"id":2,"name":"name2","img":"rew","note":"note2"},{"id":3,"name":"name3","img":"dsfs","note":"note3"},{"id":4,"name":"name4","img":"cxvxc","note":"note4"},{"id":5,"name":"name5","img":"erwe","note":"note5"}]}
班级模型是
#import "JSONModel.h" @protocol ImagesModel @end @interface ImagesModel : JSONModel @property int id; @property (strong,nonatomic) NSString* name; @property (strong,nonatomic) UIImage* img; @property (strong,nonatomic) NSString* note; @end
我收到了这个错误
Terminating app due to uncaught exception 'Bad property protocol declaration',reason: '<ImagesModel> is not allowed JSONModel property protocol,and not a JSONModel class.'
有什么帮助吗？
解决方法
我可以看到您粘贴的代码存在两个问题.
你的模型很好,但它是一个项目的模型 – 即.它是您将用于加载单个图像的模型 – 不是所有图像一次加载.因此,您需要一个模型来描述您拥有一组图像,以及另一个模型(您拥有的模型)来描述每个图像对象.
第二个问题是你的一个属性是UIImage对象,但你在JSON提要中传递字符串.
因此,要让您的示例正常工作,您需要：
#import "JSONModel.h" //define the single image object protocol @protocol ImageModel @end //define the single image model @interface ImageModel : JSONModel @property int id; @property (strong,nonatomic) NSString* img; @property (strong,nonatomic) NSString* note; @end @implementation ImageModel @end //define the top-level model for the collection of images @interface Images : JSONModel @property (strong,nonatomic) NSArray<ImageModel>* images; @end
然后读取您的JSON字符串并创建一个Images模型：
NSError* err = nil; Images* imagesCollection = [[Images alloc] initWithString:JSONstring error:&err];
然后imagesCollection.images中的每个元素都将是一个ImageModel实例.
瞧！