xcode – 使用UISearchBar调用API

我有一个显示API结果的UITableView.只要用户通过searchBar：textDidChange：键入UISearchBar,就会调用API.有效实施自动完成搜索.我的问题是加载到UITableView中的结果似乎是最后一次API调用背后的迭代.

例：
用户在UISearchBar中键入“union”,但UITableView中没有显示任何结果.用户在“联合”,“联合”之后键入任何字符,并且“联合”的API结果显示在UITableView中.当用户向下滚动结果(“联合”,但实际上是“联合”)时,“重新填充的单元格”显示“联合”结果.

SearchViewController.h

#import <UIKit/UIKit.h>

@interface SearchViewController : UIViewController <UITextFieldDelegate,UISearchBarDelegate,UITableViewDelegate,UITableViewDataSource,UISearchDisplayDelegate>{
    UITableView *searchTableView;
    UISearchBar *sBar;
    UISearchDisplayController *searchDisplayController;
}

@property (strong,nonatomic) NSArray *loadedSearches;

@end

SearchViewController.m

#import "SearchViewController.h"
#import "AFJSONRequestOperation.h"

@interface SearchViewController ()

@end

@implementation SearchViewController


- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
{
    self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil];
    if (self) {
        self.title = @"Search";
    }
    return self;
}

- (void)viewDidLoad
{
    [super viewDidLoad];
    searchTableView = [[UITableView alloc] initWithFrame:self.view.bounds];
    searchTableView.delegate = self;
    searchTableView.dataSource = self;
    [self.view addSubview:searchTableView];

    sBar = [[UISearchBar alloc] initWithFrame:CGRectMake(0,160,44)];
    sBar.placeholder = @"Bus Route to...";
    sBar.delegate = self;
    searchDisplayController = [[UISearchDisplayController alloc] initWithSearchBar:sBar contentsController:self];

    searchDisplayController.delegate = self;
    searchDisplayController.searchResultsDataSource = searchTableView.dataSource;
    searchDisplayController.searchResultsDelegate = searchTableView.delegate;

    searchTableView.tableHeaderView = sBar;
}

-(void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
    NSString *searchQuery = [NSString stringWithFormat:@"https://api.foursquare.com/v2/venues/search?ll=40.4263,-86.9177&client_id=xxx&client_secret=yyy&v=20121223&query='%@'",searchText];

    searchQuery = [searchQuery stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    NSURL *url = [[NSURL alloc] initWithString:searchQuery];

    NSURLRequest *request = [[NSURLRequest alloc] initWithURL:url];

    AFJSONRequestOperation *operation = [AFJSONRequestOperation
                                         JSONRequestOperationWithRequest:request
                                         success:^(NSURLRequest *request,NSHTTPURLResponse *response,id JSON){
                                             self.loadedSearches = JSON[@"response"][@"venues"];
                                         } failure:^(NSURLRequest *request,NSError *error,id JSON){
                                             NSLog(@"%@",error.localizedDescription);
                                         }];

    [operation start];
    [searchTableView reloadData];
}

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
    return 1;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
    return self.loadedSearches.count;
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"Cell"];

    if(cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"Cell"];
    }

    cell.textLabel.text = self.loadedSearches[indexPath.row][@"name"];

    return cell;
}

@end

如果我的问题不明确,请告诉我.

随意批评代码的其他方面,但我真的很感激我的问题的解决方案:)在此先感谢.

示例API响应 – http://pastebin.com/UZ1H2Zwy

解决方法

问题似乎是,在使用AFJSONRequestOperation进行异步操作时,在获取数据之前刷新表.所以你的模型可能正在更新,但你的tableview是一个刷新背后.尝试在块成功回调中移动[searchTableView reloadData]：

AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request
      success:^(NSURLRequest *request,id JSON)
      {
          self.loadedSearches = JSON[@"response"][@"venues"];

          // refreshing the TableView when the block gets the response
          [searchTableView reloadData];
      }
      failure:^(NSURLRequest *request,id JSON)
      {
          NSLog(@"%@",error.localizedDescription);
      }];

希望这有效.

xcode – 使用UISearchBar调用API

解决方法

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