"-String"

该字符串还包含字符串开头和结尾的两个引号,如上所述.

我想剥离第一个和最后一个字符,以便我得到以下字符串：

-String

我试过这个：

set currentParameter="-String"
echo %currentParameter:~1,-1%

这将打印出应该是的字符串：

-String

但是当我尝试像这样存储编辑过的字符串时,它会失败：

set currentParameter="-String"
set currentParameter=%currentParameter:~1,-1%
echo %currentParameter%

什么都没打印出来.我做错了什么？

这真的很奇怪.当我删除这样的字符时,它可以工作：

set currentParameter="-String"
set currentParameter=%currentParameter:~1,-1%
echo %currentParameter%

打印出来：

-String

但实际上我的批次有点复杂,并且它不起作用.我将展示我编程的内容：

@echo off

set string="-String","-String2"

Set count=0
For %%j in (%string%) Do Set /A count+=1


FOR /L %%H IN (1,1,%COUNT%) DO ( 

    echo .
        call :myFunc %%H
)
exit /b

:myFunc
FOR /F "tokens=%1 delims=," %%I IN ("%string%") Do (

    echo String WITHOUT stripping characters: %%I 
    set currentParameter=%%I
    set currentParameter=%currentParameter:~1,-1%

    echo String WITH stripping characters: %currentParameter% 

    echo .

)
exit /b   

:end

输出是：

.
String WITHOUT stripping characters: "-String"
String WITH stripping characters:
.
.
String WITHOUT stripping characters: "-String2"
String WITH stripping characters: ~1,-1
.

但我想要的是：

.
String WITHOUT stripping characters: "-String"
String WITH stripping characters: -String
.
.
String WITHOUT stripping characters: "-String2"
String WITH stripping characters: -String2
.