我需要将文件x.dtsx从位置a复制到位置b.
如果x.dtsx已经存在于b中,那么我需要将x.dtsx重命名为x_Standby.dtsx然后,将x.dtsx重命名为b后
我当前的代码如下所示：
if exists %1 rename %1 %(should be 1_standy.extension) xcopy %1 %2
如果使用命令处理器扩展(在Windows 2000及更高版本中是默认处理器扩展),则可以使用以下可选语法：
%~1 - expands %1 removing any surrounding quotes (")
%~f1 - expands %1 to a fully qualified path name
%~d1 - expands %1 to a drive letter only
%~p1 - expands %1 to a path only
%~n1 - expands %1 to a file name only
%~x1 - expands %1 to a file extension only
%~s1 - expanded path contains short names only
%~a1 - expands %1 to file attributes
%~t1 - expands %1 to date/time of file
%~z1 - expands %1 to size of file
可以组合改性剂得到复合结果：
%~dp1 - expands %1 to a drive letter and path only %~nx1 - expands %1 to a file name and extension only
所以你的命令看起来像这样：
if exist %2\%~nx1 ren %2\%~nx1 %~n1_standby%~x1
