我需要将消息从ASP.NET服务器推送到
Android设备,以便在记录状态发生变化时发出通知.所以我想使用来自GitHub的新的Microsoft SignalR Java-Client,使用Eclipse与Android ADT Bundle和Java.
> https://github.com/SignalR/java-client
> http://whathecode.wordpress.com/2014/03/20/getting-started-with-the-java-signalr-sdk/
我是Java和SignalR的新手.我有使用HTML工作的SignalR Hub和JavaScript客户端,它可以发送和接收消息.但是我无法进入下一步并让Java-Client在Eclipse / Java / Android中运行.我不知道如何注册接收广播消息.当我使用HTML / JavaScript页面发送消息时,我没有在Android应用程序中,在模拟器中,在Eclipse中收到消息.我能够
我有以下ASP.NET SignalR Hub.cs文件设置：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using Microsoft.AspNet.SignalR;
using Microsoft.AspNet.SignalR.Hubs;
using System.Threading.Tasks;
public class PtThroughputHub : Hub
{
public void SendAll(string message)
{
Clients.All.broadcastMessage(message);
}
public void SendGroup(string groupName,string message)
{
Clients.Group(groupName).broadcastMessage(message);
}
public Task JoinGroup(string groupName)
{
return Groups.Add(Context.ConnectionId,groupName);
}
public Task LeaveGroup(string groupName)
{
return Groups.Remove(Context.ConnectionId,groupName);
}
}
在JavaScript中,我还可以使用从ASP.NET Hub.cs自动生成的Hubs.js文件来通过Hub发送和接收消息.
<script src="Scripts/jquery-2.1.0.min.js"></script>
<!--Reference the SignalR library. -->
<script src="Scripts/jquery.signalR-2.0.3.min.js"></script>
<!--Reference the autogenerated SignalR hub script. -->
<script src="signalr/hubs"></script>
$(function () {
$.connection.hub.logging = true;
// Declare a proxy to reference the hub.
var ptThroughput = $.connection.ptThroughputHub;
// Create a function that the hub can call to broadcast messages.
ptThroughput.client.broadcastMessage = function (message) {
alert(message);
};
// Start the connection.
$.connection.hub.start()
.done(function () {
alert('Successfully connected as ' + $.connection.hub.id);
ptThroughput.server.joinGroup("Group1");
$('#btnSend').click(function () {
// Call the Send method on the hub.
ptThroughput.server.sendGroup('Group1','My Message Test Here!');
})
})
.fail(function () { $("#connection").text('Can not connect to SignalR hub!'); });
});
但是,在Eclipse / Java / Android中,我不确定需要使用哪些代码来接收广播消息.我能够启动连接并在以下代码示例的末尾接收connectionID但我被困在那里.我是否需要以某种方式使用.on()或.subscribe()？当我运行此代码时,我看到记录了连接ID,但我无法从html / JavaScript页面触发广播消息.没有收到任何东西,我不会在任何地方收到错误.有谁知道我在这里可能会缺少什么？
import microsoft.aspnet.signalr.client.SignalRFuture;
import microsoft.aspnet.signalr.client.hubs.HubConnection;
import microsoft.aspnet.signalr.client.hubs.HubProxy;
import microsoft.aspnet.signalr.client.hubs.SubscriptionHandler;
//Setup connection
String server = "http://Servername/Applications/ThroughputMobile/";
HubConnection connection = new HubConnection(server);
HubProxy proxy = connection.createHubProxy("ptThroughputHub");
//--HERE IS WHERE I AM NOT SURE HOW TO SET IT UP TO RECEIVE A NOTIFICATION---
//Setup to receive broadcast message
proxy.on("broadcastMessage",new SubscriptionHandler() {
@Override
public void run() {
Log.i("Test Message","broadcastMessage received...");
}
});
//---------------------------------------------------------------------------
//Start connection
SignalRFuture<Void> awaitConnection = connection.start();
try {
awaitConnection.get();
} catch (InterruptedException e) {
//Log Connection ID
Log.i("Test Message","Connection ID = " + connection.getConnectionId());
那么,我是否再次使用proxy.on()来设置接收广播通知或其他内容？我传递给方法的字符串是什么？在我的情况下,“broadcastMessage”或者也许是“sendAll”？任何帮助将不胜感激.
我没有从问题中显示的SignalR Hub调用JoinGroup()方法.您需要加入Hub才能接收广播是有道理的.所以在我的后台服务onStart()中,我调用了invoke(“JoinGroup”,“Group1”).然后我调用on()方法来设置收到的消息的处理程序. Group1是一个可配置的组名,集线器使用该名称来拆分广播,因此不同的组可以使用相同的Hub.请参阅下面的完整代码和注释解决方案块.希望这能节省一些时间！
原文链接：https://www.f2er.com/windows/363265.html//Invoke JoinGroup to start receiving broadcast messages
proxy.invoke("JoinGroup","Group1");
//Then call on() to handle the messages when they are received.
proxy.on( "broadcastMessage",new SubscriptionHandler1<String>()
{
@Override
public void run(String msg) {
Log.d("result := ",msg);
}
},String.class);
import java.util.concurrent.ExecutionException;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.app.Service;
import android.content.Context;
import android.content.Intent;
import android.os.IBinder;
import android.widget.Toast;
import microsoft.aspnet.signalr.client.*;
import microsoft.aspnet.signalr.client.hubs.*;
public class NotifyService extends Service {
@Override
public void onCreate() {
super.onCreate();
}
@SuppressWarnings("deprecation")
@Override
public void onStart(Intent intent,int startId) {
super.onStart(intent,startId);
Toast.makeText(this,"Service Start",Toast.LENGTH_LONG).show();
String server = "http://Servername/Applications/ThroughputMobile/";
HubConnection connection = new HubConnection(server);
HubProxy proxy = connection.createHubProxy("ptThroughputHub");
SignalRFuture<Void> awaitConnection = connection.start();
try {
awaitConnection.get();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ExecutionException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
//--HERE IS MY SOLUTION-----------------------------------------------------------
//Invoke JoinGroup to start receiving broadcast messages
proxy.invoke("JoinGroup","Group1");
//Then call on() to handle the messages when they are received.
proxy.on( "broadcastMessage",new SubscriptionHandler1<String>() {
@Override
public void run(String msg) {
Log.d("result := ",msg);
}
},String.class);
//--------------------------------------------------------------------------------
}
@Override
public void onDestroy() {
super.onDestroy();
}
@Override
public IBinder onBind(Intent arg0) {
return null;
}
}
