VB 增量式 PID 算法的一个问题

前端之家收集整理的这篇文章主要介绍了VB 增量式 PID 算法的一个问题前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。
Option Explicit Dim EK1 As Single,EK2 As Single Dim U As Single Dim Uk As Single,Uk1 As Single,A As Single,B As Single,C As Single,Ek As Single Dim Ti As Integer,Td As Integer,Kp As Integer Dim SP As Single,PV As Single Private Sub Command1_Click() Timer1.Enabled = True End Sub Private Sub Command2_Click() End End Sub Private Sub Timer1_Timer() Ti = Val(Text1) '读取积分时间值 Td = Val(Text2) '读取微分时间值 Kp = Val(Text3) '读取比例值 SP = Val(Text4) '设定值 Text5.Text = Val(VScroll1.Value) PV = Val(Text5) '模拟的反馈值 If Ti = 0 Then A = Kp * (1 + Td) Else A = Kp * (1 + 1 / Ti + Td) B = Kp * (1 + 2 * Td) C = Kp * Td Ek = SP - PV Uk = A * Ek - B * EK1 + C * EK2 Text6.Text = Uk '输出显示 End If EK2 = EK1 EK1 = Ek End Sub 求助各位版主,这是我编写的PID控制程序,EK表示当前的测量误差,EK1是上次测量误差,EK2是上上次误差,然后PID算法根据这三次误差输出控制量UK,正确的功能应该是根据系统设定值和实际输出值求得Ek = SP - PV,然后将这个的EK值传递给EK1,下一次测量值编程Ek,以此类推!我现在的问题是,无法将当前的测量误差传递给上一次,按着我编的程序,这三次误差实际上都等于当前的误差,求各位版主看一下问题出在哪儿!

猜你在找的VB相关文章