我有一个字符串在一个节点，我想拆分上的字符串’？并返回数组中的最后一项。
例如，在下面的块中：
<a>
<xsl:attribute name="href">
/newpage.aspx?<xsl:value-of select="someNode"/>
</xsl:attribute>
Link text
</a>
我想拆分someNode值。
编辑：
这里是VB.Net，我用来加载Xsl为我的Asp.Net页面：
Dim xslDocPath As String = HttpContext.Current.Server.MapPath("~/App_Data/someXslt.xsl")
Dim myXsltSettings As New XsltSettings()
Dim myXMLResolver As New XmlUrlResolver()
myXsltSettings.EnableScript = True
myXsltSettings.EnableDocumentFunction = True
myXslDoc = New XslCompiledTransform(False)
myXslDoc.Load(xslDocPath,myXsltSettings,myXMLResolver)
Dim myStringBuilder As New StringBuilder()
Dim myXmlWriter As XmlWriter = Nothing
Dim myXmlWriterSettings As New XmlWriterSettings()
myXmlWriterSettings.ConformanceLevel = ConformanceLevel.Auto
myXmlWriterSettings.Indent = True
myXmlWriterSettings.OmitXmlDeclaration = True
myXmlWriter = XmlWriter.Create(myStringBuilder,myXmlWriterSettings)
myXslDoc.Transform(xmlDoc,argumentList,myXmlWriter)
Return myStringBuilder.ToString()
使用递归方法：
原文链接：https://www.f2er.com/vb/256417.html<xsl:template name="output-tokens">
<xsl:param name="list" />
<xsl:variable name="newlist" select="concat(normalize-space($list),' ')" />
<xsl:variable name="first" select="substring-before($newlist,' ')" />
<xsl:variable name="remaining" select="substring-after($newlist,' ')" />
<id>
<xsl:value-of select="$first" />
</id>
<xsl:if test="$remaining">
<xsl:call-template name="output-tokens">
<xsl:with-param name="list" select="$remaining" />
</xsl:call-template>
</xsl:if>
</xsl:template>