我正在使用Ubuntu Sever 12.04.我有一个nodejs应用程序,我想这样运行：
NODE_ENV=production PORT=3001 APP_PATH=/var/www/myapp forever -a -l /var/www/myapp/forever.log -o /var/www/myapp/out.log -e /var/www/myapp/err.log /var/www/myapp/app.js
我想在系统启动时运行它,并在系统关闭时“永远停止”.我已经读过,首选方法是使用upstart脚本.这就是我尝试过的：
description "Upstart script"
start on startup
stop on shutdown
expect fork
env MYAPP_PATH="/var/www/myapp"
script
NODE_ENV=production PORT=3001 APP_PATH=$MYAPP_PATH exec forever -a -l $MYAPP_PATH/forever.log -o $MYAPP_PATH/out.log -e $MYAPP_PATH/err.log $MYAPP_PATH/app.js
end script
pre-stop script
exec forever stop $MYAPP_PATH/app.js >> $LOG
end script
它在我运行时挂起,然后它表示作业已经在运行(实际上并非如此).
任何建议如何正确地做到这一点表示赞赏.谢谢！
description "Upstart script" start on filesystem and started networking
仅供参考：don’t use “start on startup”.
stop on shutdown expect fork # Let's make sure we always have the right directory chdir /var/www/myapp env MYAPP_PATH="/var/www/myapp" env NODE_ENV=production env PORT=3001 # Is there a reason you didn't do this? env APP_PATH=$MYAPP_PATH script # Shell trick to re-direct this script's STDOUT/STDERR exec 2>> forever.log 1>> forever.log # You forgot the 'start' command. Without it,it doesn't fork. exec forever start -a -l forever.log -o out.log -e err.log app.js end script pre-stop script # Shell trick to re-direct this script's STDOUT/STDERR exec 2>> forever.log 1>> forever.log exec forever stop app.js end script
