执行以下命令按预期工作:
find /path/to/logs/ \( -type f -name '*20161005.log' \) -print0 | tar -czvf /path/to/backups/backup_logs_20161005.tar.gz --null -T -
但是,尝试在bash脚本中使用它,我得到一个空的.tar.gz文件:
#!/bin/bash now="$(date)" printf "Current date and time: $now" ## working paths LOGSPATH="/path/to/logs/" BACKPATH="/path/to/backups/" ## date to work with DATETIME=`date -d "yesterday 13:00 " '+%Y%m%d'` ## find files matching the working date and .tar.gz the result printf "\nStarting yesterday logs backup,please wait..." find "$LOGSPATH" \( -type f -name '*"$DATETIME".log' \) -print0 | tar -czvf "$BACKPATH"backup_logs_"$DATETIME".tar.gz --null -T - printf "\ndone!" ## delete backup files printf "\nRemoving logs from yesterday..." find "$LOGSPATH" -type f -name '*"$DATETIME".log' -delete printf "\ndone!\n"
输出:
Current date and time: Thu Oct 6 16:14:29 WEST 2016
Starting yesterday logs backup,please wait…
done!
Removing logs from yesterday…
done!
将此命令放在bash脚本中时我缺少什么?
更换
-name '*"$DATETIME".log'
同
-name "*$DATETIME.log"
单引号非常强,双引号允许内部$VARIABLE.