我有一些从服务器返回的数据,如下所示：
let returnedFromServer = ["title" : ["abc","def","ghi"],"time" : ["1234","5678","0123"],"content":["qwerty","asdfg","zxcvb"]]
我想把它变成这样的东西：
let afterTransformation = [["title" : "abc","time" : "1234","content": "qwerty"],["title" : "def","time" : "5678","content": "asdfg"],["title" : "ghi","time" : "0123","content": "zxcvb"]]
我目前的实施如下：
var outputArray = [[String : AnyObject]]()
for i in 0..<(returnedFromServer["time"] as [String]).count {
var singleDict = [String: AnyObject]()
for attribute in returnedFromServer {
singleDict[attribute] = returnedFromServer[attribute]?[i]
}
outputArray.append(singleDict)
}
这工作正常,但我认为这不是一个非常优雅的解决方案.鉴于Swift有一些简洁的功能,如reduce,filter和map,我想知道如果没有明确地使用循环我是否可以做同样的工作.
谢谢你的帮助！
解决方法
使用想法和字典扩展
extension Dictionary {
init(_ pairs: [Element]) {
self.init()
for (k,v) in pairs {
self[k] = v
}
}
func map<OutKey: Hashable,OutValue>(transform: Element -> (OutKey,OutValue)) -> [OutKey: OutValue] {
return Dictionary<OutKey,OutValue>(Swift.map(self,transform))
}
}
从
> What’s the cleanest way of applying map() to a dictionary in Swift?,
你可以实现这个目标
let count = returnedFromServer["time"]!.count
let outputArray = (0 ..< count).map {
idx -> [String: AnyObject] in
return returnedFromServer.map {
(key,value) in
return (key,value[idx])
}
}
