Swift 集合类

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Swift包含三种集合类

  • 数组 Array
  • 字典 Dictionary
  • 集合 Set
数组

// 数组的声明 (调用数组的构造函数)
var numbers:[Int] = [1,2,3,4]
var strings:[String] = ["one","two","three","four"]

// 空数组的声明
var emptyArray1:[Int] = []
var emptyArray2 = [Int]()
var emptyArray3 = Array<Int>()
var emptyArray4:[String] = []

var allZero = [Int](repeatElement(0,count: 5))

allZero.count // 数量
allZero.isEmpty // 是否为空
allZero[2] // 去下标值
allZero.first // 第一个元素
allZero.last // 最后一个元素

numbers[1..<3] // 取子数组
numbers.min() //最小值
numbers.max() //最大值

strings.max() //String 排序有点蒙
strings.min()
strings.contains("one") // 是否包含元素
strings.contains("five")
strings.index(of: "one") // 元素在数组的位置
strings.index(of: "two") // 元素在数组的位置
strings.index(of: "five") // 返回的是一个可选型

if let firstValue = allZero.first {
    print("the first value is " + String(firstValue))
}

数组的增 删 改
var strings:[String] = ["one","four"]

// 改
strings[0] = "1"
strings[1...3] = ["2","3","4"]

// 增
strings.append("five")
strings += ["six"]
strings.insert("seven",at: 3)

// 删
strings.removeLast()
strings.removeFirst()
strings.remove(at: 2)
strings.removeSubrange(0..<1)
strings.removeAll()



数组的遍历
// 数组的声明 (调用数组的构造函数)
var numbers:[Int] = [1,"four"]

for number in numbers {
    print(number)
}

for index in 0..<numbers.count {
    print(numbers[index])
}

for (i,number) in numbers.enumerated() {
    print("i is " + String(i) + " value is " + String(number))

字典的增删改查

var dict = ["key":"value","key1":"value1"]
var dict1 = ["key":"value","key1":1] as [String : Any]
var dict2:Dictionary<String,Any> = ["key":"value","key1":"value1"]
var dict3:[String:Any] = ["key":"value","key1":"value1"]

dict.count
dict.isEmpty

Array(dict1.values)
Array(dict.keys)

// 改
dict["key"] = "value0"
dict.updateValue("value0",forKey: "key")

// 增
dict["key3"] = "value3"
dict.updateValue("value4",forKey: "key4")

//删
dict.removeValue(forKey: "key4")
dict["key"] = nil
dict.removeAll()



for key in dict.keys {
    print(key)
}

for (key,value) in dict {
    print("\(key):\(value)")
}
原文链接:https://www.f2er.com/swift/322180.html

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