好吧，所以我创建了一个方法，应该采取“YYYY-MM-DD”形式的字符串，并吐出一个int，表示相对于它所在的星期的日期位置(无论它是否在月份之间重叠)。所以例如星期日= 1星期一= 2等等。
这里是我的代码：
func getDayOfWeek(today:String)->Int{
var formatter:NSDateFormatter = NSDateFormatter()
formatter.dateFormat = "YYYY-MM-DD"
var todayDate:NSDate = formatter.dateFromString(today)!
var myCalendar:NSCalendar = NSCalendar(calendarIdentifier: NSGregorianCalendar)
var myComponents = myCalendar.components(NSCalendarUnit.WeekdayOrdinalCalendarUnit,fromDate: todayDate)
var weekDay = myComponents.weekdayOrdinal
return weekDay
}
所以我知道NSCalendarUnit.WeekdayOrdinalCalendar是错误的，但我试过我认为大多数逻辑组合。并且也搞乱了myComponents.weekdayOrdinal例如使用mycomponents.day或.weekday。
这里是我的选择在什么使用
static var EraCalendarUnit: NSCalendarUnit { get }
static var YearCalendarUnit: NSCalendarUnit { get }
static var MonthCalendarUnit: NSCalendarUnit { get }
static var DayCalendarUnit: NSCalendarUnit { get }
static var HourCalendarUnit: NSCalendarUnit { get }
static var MinuteCalendarUnit: NSCalendarUnit { get }
static var SecondCalendarUnit: NSCalendarUnit { get }
static var WeekCalendarUnit: NSCalendarUnit { get }
static var WeekdayCalendarUnit: NSCalendarUnit { get }
static var WeekdayOrdinalCalendarUnit: NSCalendarUnit { get }
static var QuarterCalendarUnit: NSCalendarUnit { get }
static var WeekOfMonthCalendarUnit: NSCalendarUnit { get }
static var WeekOfYearCalendarUnit: NSCalendarUnit { get }
static var YearForWeekOfYearCalendarUnit: NSCalendarUnit { get }
static var CalendarCalendarUnit: NSCalendarUnit { get }
static var TimeZoneCalendarUnit: NSCalendarUnit { get }
我不清楚，因为没有DayOfWeekUnit选项(或类似的东西)。
任何推动在正确的方向获得正确的数字将是非常感激。
你正在寻找(如果我正确理解的问题)是NSCalendarUnit.CalendarUnitWeekday。 NSDateComponents的相应属性是工作日。
原文链接：https://www.f2er.com/swift/320877.html请注意，您的日期格式错误(
完整规格可以在这里找到：http://unicode.org/reports/tr35/tr35-6.html)。
使用自动类型推理可以简化函数，也可以在常量足够的地方使用变量：
func getDayOfWeek(today:String)->Int {
let formatter = NSDateFormatter()
formatter.dateFormat = "yyyy-MM-dd"
let todayDate = formatter.dateFromString(today)!
let myCalendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let myComponents = myCalendar.components(.Weekday,fromDate: todayDate)
let weekDay = myComponents.weekday
return weekDay
}
let weekday = getDayOfWeek("2014-08-27")
print(weekday) // 4 = Wednesday
然而，如果输入字符串无效，那么该函数在运行时会崩溃。正如Mike S正确地说，返回一个可选的是Swift的方式来处理这种情况：
func getDayOfWeek(today:String)->Int? {
let formatter = NSDateFormatter()
formatter.dateFormat = "yyyy-MM-dd"
if let todayDate = formatter.dateFromString(today) {
let myCalendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
let myComponents = myCalendar.components(.Weekday,fromDate: todayDate)
let weekDay = myComponents.weekday
return weekDay
} else {
return nil
}
}
其中将使用如：
if let weekday = getDayOfWeek("2014-08-27") {
print(weekday)
} else {
print("bad input")
}
(为Swift 2 / Xcode 7更新)
更新Swift 3(Xcode 8)：
func getDayOfWeek(_ today:String) -> Int? {
let formatter = DateFormatter()
formatter.dateFormat = "yyyy-MM-dd"
guard let todayDate = formatter.date(from: today) else { return nil }
let myCalendar = Calendar(identifier: .gregorian)
let weekDay = myCalendar.component(.weekday,from: todayDate)
return weekDay
}
