我有一个Swift的AnyObject对象数组。每个对象都有一个餐厅的属性,如名称,类型,loc等。如果我想保留数组中包含类型为“Sushi”的所有对象,如何过滤数组。
具有2个对象的[AnyObject]样本数组。过滤器应保留第一个对象(类型:寿司):
[<Restaurant: 0x7ff302c8a4e0,objectId: LA74J92QDA,localId: (null)> { City = "New York"; Country = "United States"; Name = Sumo Japan; Type = Sushi,Japanese,Asian; },<Restaurant: 0x7ff302daa790,objectId: 0aKFrpKN46,localId: (null)> { City = "New York"; Country = "United States"; Name = Little Italy; Type = Italian,Pizza; }]
当前代码(但我不知道过滤器是否可以搜索[AnyObject]的数组):
var query = PFQuery(className:"Restaurant") query.whereKey("RestaurantLoc",nearGeoPoint:userGeoPoint,withinMiles:50) query.limit = 2 query.findObjectsInBackgroundWithBlock { (objects: [AnyObject]!,error: NSError!) -> Void in if objects != nil { println("list of objects of nearby") println(objects) let searchString = "Sushi" let predicate = NSPredicate(format: "Type CONTAINS[cd] %@",searchString); //Line below gives error: '[AnyObject]' does not have a member named 'filteredArrayUsingPredicate' //let filteredArray = objects.filteredArrayUsingPredicate(predicate!)
您的数组,对象是一组PFObject对象。因此,要过滤数组,可以执行以下操作:
原文链接:https://www.f2er.com/swift/320444.htmllet filteredArray = objects.filter() { if let type = ($0 as PFObject)["Type"] as String { return type.rangeOfString("Sushi") != nil } else { return false } }
基于我们处理自定义餐厅对象的假设,我的原始答案如下:
您可以使用过滤器方法。
我们假设餐厅的定义如下:
class Restaurant { var city: String var name: String var country: String var type: [String]! init (city: String,name: String,country: String,type: [String]!) { ... } }
所以,假设该类型是字符串数组,你可以做一些类似的事情:
let filteredArray = objects.filter() {contains(($0 as Restaurant).type,"Sushi")}
如果您的类型数组可能为零,则可以对其进行条件展开:
let filteredArray = objects.filter() { if let type = ($0 as Restaurant).type as [String]! { return contains(type,"Sushi") } else { return false } }
具体情况将有所不同,具体取决于您的餐厅声明,您没有与我们分享,但希望这可以说明这一想法。