当函数的返回值是另一个函数时,没有办法获得返回函数的参数名称.这是一个快速语言的陷阱吗？
例如：
func makeTownGrand(budget:Int,condition: (Int)->Bool) -> ((Int,Int)->Int)?
{
guard condition(budget) else {
return nil;
}
func buildRoads(lightsToAdd: Int,toLights: Int) -> Int
{
return toLights+lightsToAdd
}
return buildRoads
}
func evaluateBudget(budget:Int) -> Bool
{
return budget > 10000
}
var stopLights = 0
if let townPlan = makeTownGrand(budget: 30000,condition: evaluateBudget)
{
stopLights = townPlan(3,8)
}
注意townPlan,townPlan(lightsToAdd：3,toLights：8)对townPlan(3,8)会更加明智,对吗？
