我有一段时间了解使用Swift 3的简单JSON序列化原则.我可以帮助解决从网站解码JSON到阵列所以我可以访问它作为jsonResult [“team1”] [“a”]等？这是相关代码：
let httprequest = URLSession.shared.dataTask(with: myurl){ (data,response,error) in
self.label.text = "RESULT"
if error != nil {
print(error)
} else {
if let urlContent = data {
do {
let jsonResult = try JSONSerialization.jsonObject(with: urlContent,options:
JSONSerialization.ReadingOptions.mutableContainers)
print(jsonResult) //this part works fine
print(jsonResult["team1"])
} catch {
print("JSON Processing Failed")
}
}
}
}
httprequest.resume()
传入的JSON是：
{
team1 = {
a = 1;
b = 2;
c = red;
};
team2 = {
a = 1;
b = 2;
c = yellow;
};
team3 = {
a = 1;
b = 2;
c = green;
};
}
谢谢
在Swift 3中,JSONSerialization.jsonObject(带有：options :)的返回类型已变为Any.
(您可以在Xcode的“快速帮助”窗格中查看它,并指向jsonResult.)
并且您不能为任何类型为Any的变量调用任何方法或下标.您需要显式类型转换才能使用Any.
if let jsonResult = jsonResult as? [String: Any] {
print(jsonResult["team1"])
}
并且NSArray的默认元素类型,NSDictionary的默认值类型也变为Any. (所有这些东西简称为“id-as-Any”,SE-0116.)
因此,如果您想深入了解JSON结构,您可能需要一些其他显式类型转换.
if let team1 = jsonResult["team1"] as? [String: Any] {
print(team1["a"])
print(team1["b"])
print(team1["c"])
}
