这不会编译:
我尝试了几件不同的事情;不同的声明Dictionary的方法,改变它的类型以匹配数据的嵌套.我也试图明确地说我的“任何”是一个集合,所以它可以被下标.没有骰子.
import UIKit import Foundation class CurrencyManager { var response = Dictionary<String,Any>() var symbols = [] struct Static { static var token : dispatch_once_t = 0 static var instance : CurrencyManager? } class var shared: CurrencyManager { dispatch_once(&Static.token) { Static.instance = CurrencyManager() } return Static.instance! } init(){ assert(Static.instance == nil,"Singleton already initialized!") getRates() } func defaultCurrency() -> String { let countryCode = NSLocale.currentLocale().objectForKey(NSLocaleCountryCode) as String let codesToCountries :Dictionary = [ "US":"USD" ] if let localCurrency = codesToCountries[countryCode]{ return localCurrency } return "USD" } func updateBadgeCurrency() { let chanCurr = defaultCurrency() var currVal :Float = valueForCurrency(chanCurr,exchange: "Coinbase")! UIApplication.sharedApplication().applicationIconBadgeNumber = Int(currVal) } func getRates() { //Network code here valueForCurrency("",exchange: "") } func valueForCurrency(currency :String,exchange :String) -> Float? { return response["current_rates"][exchange][currency] as Float } }
我们来看看
response["current_rates"][exchange][currency]
响应声明为Dictionary< String,Any>(),所以在第一个下标之后,您尝试在类型为Any的对象上调用另外两个下标.
解决方案1.将响应类型更改为嵌套字典.请注意,我添加了问号,因为任何时候您访问一个字典项,您可以返回一个可选项.
var response = Dictionary<String,Dictionary<String,Float>>>() func valueForCurrency(currency :String,exchange :String) -> Float? { return response["current_rates"]?[exchange]?[currency] }
解决方案2.解析时将每个级别转换为字典.确保仍然检查是否存在可选值.
var response = Dictionary<String,Any>() func valueForCurrency(currency :String,exchange :String) -> Float? { let exchanges = response["current_rates"] as? Dictionary<String,Any> let currencies = exchanges?[exchange] as? Dictionary<String,Any> return currencies?[currency] as? Float }