我正在尝试打开Apple Watch应用程序的父应用程序.
WKInterFaceController.openParentApplication
但是,在Xcode beta 3中,我再也找不到代码了.现在我不知道如何从watch app打开父应用程序.请帮忙.
The Objective-C method是：
原文链接：https://www.f2er.com/swift/319179.html+ (BOOL)openParentApplication:(NSDictionary *)userInfo
reply:(void (^)(NSDictionary *replyInfo,NSError *error))reply
class func openParentApplication(_ userInfo: [NSObject : AnyObject]!,reply reply: (([NSObject : AnyObject]!,NSError!) -> Void)!) -> Bool
因此,您需要将iPhone应用程序传递给reply()块,以便从WatchKit扩展程序中激活它.这是可以实现的一种方式,例如：
NSString *requestString = [NSString stringWithFormat:@"executeMethodA"]; // This string is arbitrary,just must match here and at the iPhone side of the implementation.
NSDictionary *applicationData = [[NSDictionary alloc] initWithObjects:@[requestString] forKeys:@[@"theRequestString"]];
[WKInterfaceController openParentApplication:applicationData reply:^(NSDictionary *replyInfo,NSError *error) {
NSLog(@"\nReply info: %@\nError: %@",replyInfo,error);
}];
您的iPhone应用程序的AppDelegate需要实现以下方法：
- (void)application:(UIApplication *)application handleWatchKitExtensionRequest:(NSDictionary *)userInfo reply:(void(^)(NSDictionary *replyInfo))reply {
NSString * request = [userInfo objectForKey:@"requestString"];
if ([request isEqualToString:@"executeMethodA"]) {
// Do whatever you want to do when sent the message. For instance...
[self executeMethodABC];
}
// This is just an example of what you could return. The one requirement is
// you do have to execute the reply block,even if it is just to 'reply(nil)'.
// All of the objects in the dictionary [must be serializable to a property list file][3].
// If necessary,you can covert other objects to NSData blobs first.
NSArray * objects = [[NSArray alloc] initWithObjects:myObjectA,myObjectB,myObjectC,nil];
NSArray * keys = [[NSArray alloc] initWithObjects:@"objectAName",@"objectBName",@"objectCName",nil];
NSDictionary * replyContent = [[NSDictionary alloc] initWithObjects:objects forKeys:keys];
reply(replyContent);
}
WKInterfaceController方法openParentApplication：reply：当iPhone(或iOS模拟器)解锁或锁定时,在后台启动包含应用程序.请注意,来自Apple的声明表明WatchKit扩展程序总是用于在后台启动您的iPhone应用程序,它只是模拟器的一个实现细节,它似乎在之前的测试版中在前台启动您的iPhone应用程序.
如果您想测试同时运行的WatchKit应用程序和iPhone应用程序,只需在Schemes菜单下从Xcode启动WatchKit应用程序,然后通过单击其跳板图标在模拟器中手动启动iPhone应用程序.
