我正在使用XCode在
https://github.com/nettlep/learn-swift的第一个基本操场上工作
@H_404_1@这个表达到底发生了什么？
0xC.3p0 == 12.1875@H_404_1@我已经了解了十六进制文字和特殊的“p”符号,表示2的幂.
0xF == 15 0xFp0 == 15 // 15 * 2^0@H_404_1@如果我尝试0xC.3我得到错误：十六进制浮点文字必须以指数结束. @H_404_1@我发现这很好overview of numeric literals和another deep explanation,但我没有看到解释什么.3p0的东西. @H_404_1@我已经将代码分叉并将本课程升级到XCode 7 / Swift 2 – 这是specific line.
这是
Hexadecimal exponential notation.
@H_404_1@By convention,the letter P (or p,for “power”) represents times two
raised to the power of … The number after the P is decimal and
represents the binary exponent. @H_404_1@… @H_404_1@Example: 1.3DEp42 represents hex(1.3DE) × dec(2^42). @H_404_30@ @H_404_1@以您为例,我们得到：0xC.3p0 represents 0xC.3 * 2^0 = 0xC.3 * 1 = hex(C.3) = 12.1875 where hex(C.3) = dec(12.{3/16}) = dec(12.1875)@H_404_1@例如,您可以尝试0xC.3p1(等于十六进制(C.3)* dec(2 ^ 1)),这会产生两倍的值,即24.375. @H_404_1@您还可以在操场中研究十六进制值1的二进制指数增长：// ... print(0x1p-3) // 1/8 (0.125) print(0x1p-2) // 1/4 (0.25) print(0x1p-1) // 1/2 (0.5) print(0x1p1) // 2.0 print(0x1p2) // 4.0 print(0x1p3) // 8.0 // ...@H_404_1@最后,这也在Apple`s Language Reference – Lexical Types: Floating-Point Literals中解释：@H_404_1@Hexadecimal floating-point literals consist of a 0x prefix,followed
by an optional hexadecimal fraction,followed by a hexadecimal
exponent. The hexadecimal fraction consists of a decimal point
followed by a sequence of hexadecimal digits. The exponent consists of an upper- or lowercase p prefix followed by a sequence of decimal digits that indicates what power of 2 the value preceding the p is multiplied by. For example,0xFp2 represents 15 x 2^2,which evaluates to 60. Similarly,0xFp-2 represents 15 x 2^-2,which evaluates to 3.75. @H_404_30@
