我的场景中有两个父SKNode,其zPosition为1(node1)和2(node2).我想要实现的是node2应始终分层ABOVE node1.但不幸的是,node1的子节点(其zPosition为1-50)都位于node2的子节点之上(当前没有zPosition).有没有办法解决这个问题(除了给node2一个超过50的zPosition)？也许是某种布尔参数来设置所有子节点的zPosition相对于它的父节点？任何帮助将不胜感激！
编辑：为了更清楚,这里是所有元素的层次结构：
> node1：SKNode(zPosition 1)
> child1：SKNode(zPosition 1)
> child2：SKNode(zPosition 2)
> child3：SKNode(zPosition 3)
> ……
> child50：SKNode(zPosition 50)
> node2：SKNode(zPosition 2)
> child1：SKLabelNode(没有zPosition)
> child2：SKLabelNode(没有zPosition)
> child3：SKLabelNode(没有zPosition)
> ……
> child50：SKLabelNode(没有zPosition)
EDIT2：这是我的GameScene类的一个非常简化的版本：
import SpriteKit
class GameScene: SKScene {
let gameNode = SKNode()
let node1 = SKNode()
let node2 = SKNode()
let nodeSize:CGFloat = 50.0
let spacing:CGFloat = 5.0
required init(coder aDecoder: NSCoder) {
fatalError("NSCoder not supported")
}
override init(size: CGSize) {
super.init(size: size)
self.addChild(gameNode)
node1.name = "node1"
node2.name = "node2"
node1.zPosition = 1
node2.zPosition = 2
gameNode.addChild(node1)
gameNode.addChild(node2)
// add children to node1
for i in 1..<10 {
let child = SKSpriteNode(color: UIColor.redColor(),size: CGSize(width: nodeSize,height: nodeSize))
child.position = CGPointMake((nodeSize + spacing) * CGFloat(i),0)
child.zPosition = CGFloat(i)
self.node1.addChild(child)
}
// add children to node2
for i in 1..<10 {
let child = SKLabelNode(fontNamed: "Avenir Black")
child.position = CGPoint(x: (nodeSize + spacing) * CGFloat(i),y: 0)
child.text = "label\(i)"
child.fontSize = 10
child.fontColor = UIColor.blackColor()
self.node2.addChild(child)
}
}
}
运行它时,您可以看到只有node2(label1)的第一个子节点位于node1的第一个子节点之上(因为它们具有相同的zPosition).所有其他的都在node1的子节点下面.
Maintaining the order of a node’s children can be a lot of work. Instead,you can give each node an explicit height in the scene. You do this by setting a node’s zPosition property. The z position is the node’s height relative to its parent node,much as a node’s position property represents its x and y position relative to parent’s position. So you use the z position to place a node above or below the parent’s position.
When you take z positions into account,here is how the node tree is
rendered:
- Each node’s global z position is calculated.
- Nodes are drawn in order from smallest z value to largest z value.
- If two nodes share the same z value,ancestors are rendered first,and siblings are rendered in child order.
我发现 – 我不知道它是这样的 – 是孩子zPosition计算总结他们的父母zPosition,所以如果node1.zPosition(node1的)child3.zPosition = 4,和node2.zPosition(node2的)child3 .zPosition = 3,node1的孩子将被涂在上面.
解决方案：将node2.zPosition设置为大于(node1)的lastChild.zPosition node1.zPosition.
