database – SQLite仅在值不为空时更新列

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查询:UPDATE item_table SET field1 = field1_spanish,field2 = field2_spanish;

问题:如果field1_spanish不为空,如何仅使用field1_spanish更新field1?如果field2_spanish不为空,我想用field2_spanish更新field2.

谢谢!

解决方法

http://sqlfiddle.com/#!5/58554/1

update
  item_table
set
  field1 = coalesce(field1_spanish,field1),field2 = coalesce(field2_spanish,field2)

coalesce()函数将返回传递给它的第一个参数,该参数不为null.所以在这种情况下,由于field2_spanish为null,它将field2设置为field2(基本上什么都不做).

支持空字符串和NULL值,请尝试以下操作:
http://sqlfiddle.com/#!5/b344f/3

update
  item_table
set
  field1 = case when coalesce(field1_spanish,'') = '' then
            field1
           else
            field1_spanish
           end,field2 =  case when coalesce(field2_spanish,'') = '' then
            field2
           else
            field2_spanish
           end

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