解决方法
sqlite中没有内置数字格式化功能,但您可以创建一个
user-defined function来创建一个.
这是一个有效的例子.使用整数,需要调整浮点数.
#import <sqlite3.h> static char *sepnum(int num,char *buf,size_t buflen,char sepch) { int len = 0,negative = 0; if (!buf || buflen == 0) return buf; if (num < 0) { negative = 1; num = abs(num); } for (int i=1;;i++) { if (buflen>len+1) buf[len++] = '0' + (num % 10); num /= 10; if (num==0) break; if ((i % 3) == 0 && buflen>len+1) buf[len++] = sepch; } if (negative && buflen>len+1) buf[len++] = '-'; for (int i=0;i<len/2;i++) { buf[len] = buf[i]; buf[i] = buf[len-i-1]; buf[len-i-1] = buf[len]; } if (buflen>len) buf[len] = '\0'; else buf[0] = '\0'; return buf; } static void nformat(sqlite3_context *context,int argc,sqlite3_value **argv) { if (argc == 1) { int num = sqlite3_value_int(argv[0]); char buf[500] = ""; if (sepnum(num,buf,sizeof(buf),',')) { sqlite3_result_text(context,-1,sqlITE_TRANSIENT); return; } } sqlite3_result_null(context); } int main(int argc,char *argv[]) { sqlite3 *db; sqlite3_open(":memory:",&db); sqlite3_stmt *stmt; sqlite3_create_function(db,"nformat",1,sqlITE_UTF8,NULL,&nformat,NULL); sqlite3_prepare(db,"select nformat(1234)",&stmt,NULL); sqlite3_step(stmt); printf("[%s]\n",sqlite3_column_text(stmt,0)); }