insert into payIncome(time,inout,money,type) values("2014-05-12","支出",25.5,"衣服");
insert into payIncome(time,35.5,"饮食");
insert into payIncome(time,"收入",135.5,"打工");
insert into payIncome(time,245.5,"工资");
insert into payIncome(time,type) values("2013-05-12",3245.5,"奖金");
insert into payIncome(time,type) values("2014-04-12",500,"学费");
.mode list
.mode line
select * from payIncome;
IDtime inout money type content
-------------------- ---------- -------------------- ----------
12014-05-12 支出 25.5 衣服
22014-05-12 支出 35.5 饮食
32014-05-12 收入 135.5 打工
42014-05-12 收入 245.5 工资
52013-05-12 收入 3245.5 奖金
62014-04-12 支出 500 学费
select inout,type,sum(money) as money frompayIncome where time like "2014-05%"
group by inout,type having sum(money) >100 order by sum(money) desc;
inouttype money
-------------------- ----------
收入 工资 245.5
收入 打工 135.5
select inout,sum(money) as money frompayIncome group by inout,type having
sum(money) > 100 order by sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
select inout,sum(money) as money frompayIncome group by type,inout having
sum(money) > 100 order by sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
select inout,sum(money) as money frompayIncome group by type,inout order b
y sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
sqlite> select inout,sum(money) asmoney from payIncome group by type,inout
order by sum(money) desc,inout;
select inout,inout order b
y sum(money) desc,inout;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
select inout,inout desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
delete from payIncome where money=500 andtype="学费" andinout="收入";
select inout,inout order b
y sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
支出 学费 500
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
delete from payIncome where money=500 andtype="学费";
select inout,inout order b
y sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
update payIncome set type="理发" where money=25.5 andinout="收入";
select inout,inout order b
y sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 衣服 25.5
update payIncome set type="理发" where money=25.5 andinout="支出";
select inout,inout order b
y sum(money) desc;
inouttype money
-------------------- ----------
收入 奖金 3245.5
收入 工资 245.5
收入 打工 135.5
支出 饮食 35.5
支出 理发 25.5
create table user(id integer primary keyautoincrement,name varchar(10),pwd varc
har(10));
sqlite> .tables
.tables
android_Metadata payIncomeuser incomeItem payItem
sqlite> drop table user;
drop table user;
sqlite> .tables
.tables
android_Metadata incomeItem payIncome payItem
sqlite>
