我正在使用Spring Data JPA和Spring Boot.应用程序的布局是这样的
main
+-- java
+-- com/lapots/game/monolith
+-- repository/relational
+--RelationalPlayerRepository.java
+-- web
+--GrandJourneyMonolithApplication.java
+-- config
+-- RelationalDBConfiguration.java
test
+-- java
+-- com/lapots/game/monolith
+-- repository/relational
+-- RelationalPlayerRepositoryTests.java
+-- web
+-- GrandJourneyMonolithApplicationTests.java
我的对象的存储库看起来像这样
public interface RelationalPlayerRepository extends JpaRepository另外,对于存储库,我提供了一个配置
@Configuration
@EnableJpaRepositories(basePackages = "com.lapots.game.monolith.repository.relational")
@EntityScan("com.lapots.game.monolith.domain")
public class RelationalDBConfiguration {
}
我的主要应用程序如下所示
@SpringBootApplication
@ComponentScan("com.lapots.game.monolith")
public class GrandJourneyMonolithApplication {
@Autowired
private RelationalPlayerRepository relationalPlayerRepository;
public static void main(String[] args) {
SpringApplication.run(GrandJourneyMonolithApplication.class,args);
}
@Bean
public CommandLineRunner initPlayers() {
return (args) -> {
Player p = new Player();
p.setLevel(10);
p.setName("Master1909");
p.setClazz("warrior");
relationalPlayerRepository.save(p);
};
}
}
应用程序测试看起来像这样
@RunWith(SpringRunner.class)
@SpringBootTest
public class GrandJourneyMonolithApplicationTests {
@Test
public void contextLoads() {
}
}
存储库的测试看起来像这样
@RunWith(SpringRunner.class)
@DataJpaTest
public class RelationalPlayerRepositoryTests {
@Autowired
private TestEntityManager entityManager;
@Autowired
private RelationalPlayerRepository repository;
@Test
public void testBasic() {
Player expected = createPlayer("Master12","warrior",10);
this.entityManager.persist(expected);
List但是当我尝试运行测试时,我得到了错误
Tests run: 1,Failures: 0,Errors: 1,Skipped: 0,Time elapsed: 0.041 sec <<< FAILURE! - in com.lapots.game.monolith.repository.relational.RelationalPlayerRepositoryTests
initializationError(com.lapots.game.monolith.repository.relational.RelationalPlayerRepositoryTests) Time elapsed: 0.006 sec <<< ERROR!
java.lang.IllegalStateException: Unable to find a @SpringBootConfiguration,you need to use @ContextConfiguration or @SpringBootTest(classes=...) with your test
at org.springframework.util.Assert.state(Assert.java:70)
at org.springframework.boot.test.context.SpringBootTestContextBootstrapper.getOrFindConfigurationClasses(SpringBootTestContextBootstrapper.java:202)
at org.springframework.boot.test.context.SpringBootTestContextBootstrapper.processMergedContextConfiguration(SpringBootTestContextBootstrapper.java:137)
at org.springframework.test.context.support.AbstractTestContextBootstrapper.buildMergedContextConfiguration(AbstractTestContextBootstrapper.java:409)
at org.springframework.test.context.support.AbstractTestContextBootstrapper.buildDefaultMergedContextConfiguration(AbstractTestContextBootstrapper.java:323)
at org.springframework.test.context.support.AbstractTestContextBootstrapper.buildMergedContextConfiguration(AbstractTestContextBootstrapper.java:277)
at org.springframework.test.context.support.AbstractTestContextBootstrapper.buildTestContext(AbstractTestContextBootstrapper.java:112)
at org.springframework.boot.test.context.SpringBootTestContextBootstrapper.buildTestContext(SpringBootTestContextBootstrapper.java:82)
at org.springframework.test.context.TestContextManager.问题是什么？
域名播放器就像这样
@Data
@Entity
@Table(schema = "app",name = "players")
public class Player {
@Id
@GeneratedValue
private Long id;
@Transient
Set最佳答案
