java – 使用两个对象进行Spring Form验证

Spring Boot应用程序遇到了一个复杂的问题,我现在一直试图解决这个问题,我希望有人可以帮助我.我删除了项目的所有其他部分,并尽量使其尽可能简单.如果你去localhost：8080,会有一个带有两个文本框的表单,可以输入两个名称,还有一个Submit按钮.第一个名称将存储在Nominee对象中,第二个名称将存储在Submitter对象中.单击“提交”时,它将对字段执行验证,以确保它们都不为空.我将发布下面的代码并在最后解释我的问题.

Application.java

@SpringBootApplication
@EnableJms
@EnableWebMvc
public class Application {

    public static void main(String[] args) throws Exception {
        // Launch the application
        SpringApplication.run(Application.class,args);
    }
}

WebController.java

@Controller
public class WebController extends WebMvcConfigurerAdapter {
    protected static final Logger LOG = LoggerFactory.getLogger(WebController.class);

    @InitBinder("nominee")
    protected void initNomineeBinder(WebDataBinder binder) {
        binder.setValidator(new NomineeValidator());
    }

    @InitBinder("submitter")
    protected void initSubmitterBinder(WebDataBinder binder) {
        binder.setValidator(new SubmitterValidator());
    }

    @Override
    public void addViewControllers(ViewControllerRegistry registry) {
        registry.addViewController("/success").setViewName("success");
    }

    @RequestMapping(value="/",method=RequestMethod.GET)
    public String showForm(Model model) {
        model.addAttribute("nominee",new Nominee());
        model.addAttribute("submitter",new Submitter());
        return "form";
    }

    @RequestMapping(value="/",method=RequestMethod.POST)
    public String checkPersonInfo(@modelattribute(value="nominee") @Valid Nominee nominee,@modelattribute(value="submitter") @Valid Submitter submitter,BindingResult bindingResult,@Valid Model model) {
        LOG.info("Nominee to string: " + nominee.toString());
        LOG.info("Submitter to string: " + submitter.toString());
        LOG.info("bindingResult to string: " + bindingResult.toString());
        if (bindingResult.hasErrors()) {
            return "form";
        }

        return "redirect:/success";
    }
}

Nominee.java

import lombok.Data;

@Data
public class Nominee {
    private String name;
}

NomineeValidatior.java

public class NomineeValidator implements Validator {

    public boolean supports(Class clazz) {
        return Nominee.class.equals(clazz);
    }

    public void validate(Object object,Errors errors) {
        ValidationUtils.rejectIfEmpty(errors,"name","This field is empty.");
    }
}

Submitter.java

import lombok.Data;

@Data
public class Submitter {
    private String sname;
}

SubmitterValidator.java

public class SubmitterValidator implements Validator {

    public boolean supports(Class clazz) {
        return Submitter.class.equals(clazz);
    }

    public void validate(Object object,"sname","This field is empty.");
    }
}

form.html


success.html


如果我将第一个文本字段留空(并填写或不填写第二个文本字段),屏幕上会显示一条错误消息,内容如下：

Whitelabel Error Page
This application has no explicit mapping for /error,so you are seeing this as a fallback. Tue May 12 13:10:17 AEST 2015 There was an unexpected error (type=Bad Request,status=400). Validation Failed for object='nominee'. Error count: 1

我不知道如何修复它,以便将第一个文本框留空不会导致whitelabel错误页面.如果我将第二个文本字段留空但填写第一个,它的行为完全正常,所以我不确定为什么它会导致错误,如果我反过来尝试它.任何帮助解决这个问题将不胜感激.
另外,你可能已经注意到我必须在提名和提交者中使用’name’和’sname’作为我的变量,如果我将它们都设置为’name’,那么它就无法正常工作.如果有任何方法可以编辑它以便它们都可以使用“名称”,我很想知道如何.
编辑：找到解决方案.在WebController中,checkPersonInfo需要为每个要验证的对象单独的BindingResult. BindingResult需要紧跟在每个@Valid对象之后的方法参数中.
所以,在WebController.java中,这个：

@RequestMapping(value="/",method=RequestMethod.POST)
public String checkPersonInfo(@modelattribute(value="nominee") @Valid Nominee nominee,@Valid Model model) {
    LOG.info("Nominee to string: " + nominee.toString());
    LOG.info("Submitter to string: " + submitter.toString());
    LOG.info("bindingResult to string: " + bindingResult.toString());
    if (bindingResult.hasErrors()) {
        return "form";
    }

    return "redirect:/success";
}

需要变成这样：

@RequestMapping(value="/",BindingResult bindingResultNominee,BindingResult bindingResultSubmitter) {
    LOG.info("Nominee to string: " + nominee.toString());
    LOG.info("Submitter to string: " + submitter.toString());
    if (bindingResultNominee.hasErrors() || bindingResultSubmitter.hasErrors()) {
        return "form";
    }

    return "redirect:/success";
}

(模型对象已被删除,因为它从未在任何地方实际使用,如果您需要使用@Valid验证它,那么您将添加第三个BindingResult对象.)


最佳答案
找到了解决方案.在WebController中,这个：

    @RequestMapping(value="/",@Valid Model model) {
    LOG.info("Nominee to string: " + nominee.toString());
    LOG.info("Submitter to string: " + submitter.toString());
    LOG.info("bindingResult to string: " + bindingResult.toString());
    if (bindingResult.hasErrors()) {
        return "form";
    }

    return "redirect:/success";
}

需要变成这样：

    @RequestMapping(value="/",那么您将添加第三个BindingResult对象.)

 原文链接：https://www.f2er.com/spring/432601.html

java – 使用两个对象进行Spring Form验证

猜你在找的Spring相关文章