在我的应用程序中,我使用Spring Data和hibernate作为JPA提供程序来持久化和读取数据.
我有顶级实体类:
@Entity
@Getter @Setter
@Table(name = "operation")
@Inheritance(strategy = InheritanceType.JOINED)
@EqualsAndHashCode(of = {"operationId"})
public abstract class Operation implements Serializable {
public static final int OPERATION_ID_LENGTH = 20;
@Id
@Column(name = "operation_id",length = OPERATION_ID_LENGTH,nullable = false,columnDefinition = "char")
private String operationId;
@Column(name = "operation_type_code")
@Getter(AccessLevel.NONE)
@Setter(AccessLevel.NONE)
private String operationTypeCode;
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "begin_timestamp",nullable = false)
private Date beginTimestamp = new Date();
@Temporal(TemporalType.TIMESTAMP)
@Column(name = "end_timestamp")
private Date endTimestamp;
@Column(name = "operation_number",length = 6,columnDefinition = "char")
private String operationNumber;
@Enumerated(EnumType.STRING)
@Column(name = "operation_status",length = 32,nullable = false)
private OperationStatus status;
@ManyToOne(optional = false)
@JoinColumn(name = "user_id")
private User user;
@ManyToOne
@JoinColumn(name = "terminal_id")
private Terminal terminal;
@Column(name = "training_mode",nullable = false)
private boolean trainingMode;
}
对于继承的类,我有相应的存储库:
public interface ConcreteOperationRepository extends JpaRepository
我用以下方法进行集成测试:
@Transactional
@Test
public void shouldFindOperationByPeriodAndStatusAndWorkstationId() {
Date from = new Date(Calendar.getInstance().getTime().getTime());
List
但是由于结果为空而我使用MysqL数据库时此测试失败(但是当我切换到HsqlDB时通过)
此外,如果我在测试开始时将延迟“Thread.sleep(1000)”延迟一秒,就在第一行之后,则此测试通过.
最佳答案
在JPA中,日期需要时间提示.通常,您可以在设置JPA Query参数时设置TemporalType:
query.setParameter("from",from),TemporalType.TIMESTAMP);
使用Spring Data,您需要使用@Temporal
注释,因此您的查询将变为:
@Query("SELECT o FROM ConcreteOperation o WHERE o.beginTimestamp BETWEEN :from AND :to AND o.status = :status AND o.terminal.deviceId = :deviceId AND o.trainingMode = :trainingMode")
Collection