正则表达式 – 将字符串解析为哈希

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@H_502_1@
我有一个字符串:

<https://gitlab.me.com/api/v3/projects/all?page=2&per_page=5>;
rel="next",<https://gitlab.me.com/api/v3/projects/all?page=1&per_page=5>;
rel="first",<https://gitlab.me.com/api/v3/projects/all?page=8&per_page=5>;
rel="last"

所以格式是

(<val>; rel="key")*

我想用以下格式将其解析为哈希:

next => https://gitlab.me.com/api/v3/projects/all?page=2&per_page=5
first => https://gitlab.me.com/api/v3/projects/all?page=1&per_page=5
last => https://gitlab.me.com/api/v3/projects/all?page=8&per_page=5

在Java中,我将使用正则表达式模式来提取每个键=>价值对并将它们放入地图中.模式将是这样的:

<([^>]++)>;\s*rel="([^"]++)"

哪个会给我第二个匹配组中的键和第一个匹配组中的值.同样的方法是实现这一目标的最好方法是Perl,还是我能做些什么?

附:我使用Perl而不是Java的原因是服务器没有Java.

解决方法

您可以在“,”上拆分字符串,然后使用映射创建哈希:

#!/usr/bin/env perl

use strict;
use warnings;

my $str = 'https://gitlab.me.com/api/v3/projects/all?page=2&per_page=5; rel="next",https://gitlab.me.com/api/v3/projects/all?page=1&per_page=5; rel="first",https://gitlab.me.com/api/v3/projects/all?page=8&per_page=5; rel="last"';

my %hash = map { 
    my ($v,$k) = $_ =~ /\s*([^;]+);\s*rel="([^"]+)".*/; 
    $k => $v;
} split ',',$str;

foreach my $key (keys %hash) {
    print "$key => $hash{$key}\n"
}

输出

first => https://gitlab.me.com/api/v3/projects/all?page=1&per_page=5
next => https://gitlab.me.com/api/v3/projects/all?page=2&per_page=5
last => https://gitlab.me.com/api/v3/projects/all?page=8&per_page=5

更新

使用新字符串,您可以:

$str = q(<https://gitlab.me.com/api/v3/projects/all?page=2&per_page=5>; rel="next",<https://gitlab.me.com/api/v3/projects/all?page=1&per_page=5>; rel="first",<https://gitlab.me.com/api/v3/projects/all?page=8&per_page=5>; rel="last");

my %hash = map { 
    my ($v,$k) = $_ =~ /<([^>]+)>;\s*rel="([^"]+)".*/; 
    $k => $v;
} split ',$str;

得到相同的结果.

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