'registry/rabbit','registry/rabbit:3','rabbit','rabbit:3'
试图在上述四种情况下提出一种与兔子相匹配的正则表达式.似乎很容易,但我的正则表达式让我失望.
解决方法
你可以试试：
(?:[a-z]+/)?([a-z]+)(?::[0-9]+)?
但是您需要阅读规范以将a-z和0-9替换为所有可能的字符.
或者,此正则表达式将捕获容器名称,而不考虑除/和::之外的规范
(?:.+/)?([^:]+)(?::.+)?
样本数据和测试
def s = [
'registry.example.com/org/image-name','registry/org/image-name','registry/image-name','image-name','registry.example.com/org/image-name:version','registry/org/image-name:version','registry/image-name:version','image-name:version',]
s.forEach {
def image = (s =~ "(?:.+/)?([^:]+)(?::.+)?")[0][1]
println image
assert image == 'image-name'
}
将输出：
image-name image-name image-name image-name image-name image-name image-name image-name
