我有以下文字：
application ONE {
protocol tcp;
destination-port 50;
}
application TWO {
protocol udp;
destination-port 51;
inactivity-timeout 800;
}
application THREE {
protocol udp;
destination-port 500;
}
我需要搜索每个应用程序,当协议是udp时,如果不活动超时不同于1800(应用程序TWO)或协议是udp并且没有定义不活动(应用程序三).
我用正则表达式解决了第一个案例：
(?s)(?=protocol udp).*(inactivity-timeout (?!1800))
但我还没有办法获得第二个.
有什么建议？
解决方法
你用Java标记了这一点,所以我给你一个Java解决方案,虽然我不确定你的帖子是否是你想要的.
我个人会将问题分成两部分.首先,提取应用程序,然后检查应用程序是否满足要求.这是我的尝试.
public class ApplicationReadOut {
public static String EXAMLPLE = "application ONE {\r\n"
+" protocol tcp;\r\n"
+" destination-port 50;\r\n"
+"}\r\n"
+"application TWO {\r\n"
+" protocol udp;\r\n"
+" destination-port 51;\r\n"
+" inactivity-timeout 800;\r\n"
+"}\r\n"
+"application THREE {\r\n"
+" protocol udp;\r\n"
+" destination-port 500;\r\n"
+"}\r\n";
public boolean checkApplication(String app) {
String[] lines = app.split("\r\n");
boolean udp = false;
boolean timeoutDiffers = true;
boolean timeoutMentioned = false;
for (String line : lines) {
if (line.trim().equals("protocol udp;"))
udp = true;
if (line.trim().equals("inactivity-timeout 1800;"))
timeoutDiffers = false;
if (line.trim().startsWith("inactivity-timeout "))
timeoutMentioned = true;
}
return udp & (timeoutDiffers | !timeoutMentioned);
}
public String[] extractApplications(String text) {
String[] applications = text.split("}(\r*\n*)*");
// the \r\n thing is to ignore blank lines in between applications
ArrayList<String> goodApps = new ArrayList<String>(applications.length);
for (int i = 0; i < applications.length; i++) {
applications[i] += "}"; // this was removed by split
if (checkApplication(applications[i]))
goodApps.add(applications[i]);
}
return goodApps.toArray(new String[0]);
}
public static void main(String[] args) {
ApplicationReadOut aro = new ApplicationReadOut();
System.out.println(Arrays.toString(aro.extractApplications(EXAMLPLE)));
}
}
我希望这很有用,你可以修改它以满足你的需求:-)
