Regex.Replace(
contents,@"(\[assembly: Assembly(File)?Version\("").*(""\)\])","$1" + version + "$3"
);
问题是该版本是类似“1.5.3.0”，所以当替换被评估时，它看到“$ 11.5.3.0 $ 3”，并且可能是寻找第十一个捕获的组，因为它出来了：
$11.5.3.0")]
如果在$ 1之后粘贴一个空格，它可以正常工作。我需要放在哪里才能摆脱第二个数字而不插入字符？
这是一个说明的代码片段(see also on ideone.com)：
Console.WriteLine(Regex.Replace("abc","(.)","$11")); // $11$11$11
Console.WriteLine(Regex.Replace("abc","${1}1")); // a1b1c1
Console.WriteLine(Regex.Replace("abc","(?<x>.)","${x}1")); // a1b1c1
此行为明确记录：
07002 – 07003
07004
The
$numberlanguage element includes the last substring matched by thenumbercapturing group in the replacement string,wherenumberis the index of the capturing group.If
numberdoes not specify a valid capturing group defined in the regular expression pattern,$numberis interpreted as a literal character sequence that is used to replace each match.07005
The
${name}language element substitutes the last substring matched by thenamecapturing group,wherenameis the name of a capturing group defined by the(?<name>)language element.If
namedoes not specify a valid named capturing group defined in the regular expression pattern,${name}is interpreted as a literal character sequence that is used to replace each match.
