我正在做一些正规表达体操.我为自己设置了尝试搜索C#代码的任务,其中使用了as-operator而没有在合理的空间内进行空检查.现在我不想解析C#代码.例如.我想捕获诸如的代码片段
var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(x1.a == y1.a)
但是,没有捕获
var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(x1 == null)
也不是那件事
var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(somethingunrelated == null) {...}
if(x1.a == y1.a)
因此,任何随机空检查都将被视为“良好检查”,因此未被发现.
问题是：我如何匹配某些东西,同时确保在其周围环境中找不到其他东西.
我尝试过天真的方法,寻找’as’然后在150个字符内做一个负面的预测.
\bas\b.{1,150}(?!\b==\s*null\b)
上述正则表达式与所有上述示例匹配.我的直觉告诉我,问题是前瞻然后做负面预测会发现许多情况,即前瞻没有找到’== null’.
如果我尝试否定整个表达式,那么这也无济于事,因为这将匹配大多数C#代码.
我喜欢正则表达式体操！这是一个注释的PHP正则表达式：
原文链接：https://www.f2er.com/regex/356871.html$re = '/# Find all AS,(but not preceding a XX == null).
\bas\b # Match "as"
(?= # But only if...
(?: # there exist from 1-150
[\S\s] # chars,each of which
(?!==\s*null) # are NOT preceding "=NULL"
){1,150}? # (and do this lazily)
(?: # We are done when either
(?= # we have reached
==\s*(?!null) # a non NULL conditional
) #
| $ # or the end of string.
)
)/ix'
这里是Javascript风格：
re = /\bas\b(?=(?:[\S\s](?!==\s*null)){1,150}?(?:(?===\s*(?!null))|$))/ig;
这个确实让我头疼了一点……
这是我正在使用的测试数据：
text = r""" var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(x1.a == y1.a)
however,not capture
var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(x1 == null)
nor for that matter
var x1 = x as SimpleRes;
var y1 = y as SimpleRes;
if(somethingunrelated == null) {...}
if(x1.a == y1.a)"""
