给定此数据框：
生产：
即将多索引的分组级别填充到标准长度(行数)
在相当大的多索引数据帧(〜几千列和几百万行)上,是否有一种合理的快速方法？
这是给定的数据框字典,以供快速参考：
d = {'region': {0: 'intro',1: 'intro',2: 'intro',3: 'mid',4: 'mid',5: 'start',6: 'start',7: 'start',8: 'title',9: 'title'},'feat_index': {0: 9,1: 3,2: 0,3: 7,4: 8,5: 2,6: 4,7: 1,8: 6,9: 5},'position_in_region': {0: 422,1: 5834,2: 8813,3: 3187,4: 9407,5: 997,6: 3154,7: 8416,8: 5408,9: 8421},'document_0': {0: 0.39,1: 0.79,2: 0.01,3: 0.55,4: 0.99,5: 0.67,6: 0.61,7: 0.84,8: 0.15,9: 0.23},'document_1': {0: 0.8,1: 0.06,2: 0.92,3: 0.74,4: 0.06,5: 0.96,6: 0.57,7: 0.19,8: 0.29,9: 0.24},'document_2': {0: 0.81,1: 0.15,2: 0.19,3: 0.17,4: 0.11,5: 0.34,6: 0.8,7: 0.03,8: 0.67,9: 0.46}}
df = pd.DataFrame(d).set_index(['region','feat_index','position_in_region'])
最佳答案
您可以使用由
numpy.repeat和numpy.tile创建的帮助器DataFrame与左联接合并：
#get number of new rows by Counter.most_common(1)
from collections import Counter
no_vals = Counter(df.index.labels[0]).most_common(1)[0][1]
print(no_vals)
3
df1 = pd.DataFrame({'region':np.repeat(df.index.levels[0],no_vals),'id': np.tile(np.arange(no_vals),len(np.unique(df.index.labels[0])))})
print (df1)
region id
0 intro 0
1 intro 1
2 intro 2
3 mid 0
4 mid 1
5 mid 2
6 start 0
7 start 1
8 start 2
9 title 0
10 title 1
11 title 2
#MultiIndex to columns
df = df.reset_index()
#new could with counter of regions
df.insert(1,'id',df.groupby('region').cumcount())
#merge,remove helper id columns and create MultiIndex
df = (df1.merge(df,how='left')
.drop('id',1)
.set_index(['region','position_in_region']))
print (df)
document_0 document_1 document_2
region feat_index position_in_region
intro 9.0 422.0 0.39 0.80 0.81
3.0 5834.0 0.79 0.06 0.15
0.0 8813.0 0.01 0.92 0.19
mid 7.0 3187.0 0.55 0.74 0.17
8.0 9407.0 0.99 0.06 0.11
NaN NaN NaN NaN NaN
start 2.0 997.0 0.67 0.96 0.34
4.0 3154.0 0.61 0.57 0.80
1.0 8416.0 0.84 0.19 0.03
title 6.0 5408.0 0.15 0.29 0.67
5.0 8421.0 0.23 0.24 0.46
NaN NaN NaN NaN NaN
DataFrame.reindex和MultiIndex.from_product的另一种解决方案：
from collections import Counter
no_vals = Counter(df.index.labels[0]).most_common(1)[0][1]
print(no_vals)
3
mux = pd.MultiIndex.from_product([df.index.levels[0],np.arange(no_vals)],names=['region','id'])
print (mux)
MultiIndex(levels=[['intro','mid','start','title'],[0,1,2]],codes=[[0,2,3,3],'id'])
df = df.reset_index(level=[1,2]).set_index(df.groupby(level=0).cumcount(),append=True)
df = (df.reindex(mux).reset_index(level=1,drop=True)
.set_index(['feat_index','position_in_region'],append=True))
print (df)
document_0 document_1 document_2
region feat_index position_in_region
intro 9.0 422.0 0.39 0.80 0.81
3.0 5834.0 0.79 0.06 0.15
0.0 8813.0 0.01 0.92 0.19
mid 7.0 3187.0 0.55 0.74 0.17
8.0 9407.0 0.99 0.06 0.11
NaN NaN NaN NaN NaN
start 2.0 997.0 0.67 0.96 0.34
4.0 3154.0 0.61 0.57 0.80
1.0 8416.0 0.84 0.19 0.03
title 6.0 5408.0 0.15 0.29 0.67
5.0 8421.0 0.23 0.24 0.46
NaN NaN NaN NaN NaN