有没有一种方法可以控制在Python argparse中评估参数的顺序

让我们来看下面的例子.解析器包含两个参数-inputfile和verbosity. Set_verbosity_level()函数用于将模块级/全局变量(在我的现实生活中为程序包级变量)的值控制为0-4. CheckFile()函数在输入文件中执行测试(实际情况取决于类型).
我想根据详细程度在CheckFile()中打印消息.问题是argparse在Set_verbosity_level()之前调用CheckFile(),因此详细程度级别始终为0 /默认值在CheckFile中…

所以我的问题是是否有任何解决方案可以迫使argparse先评估一些论点…

    import argparse

    VERBOSITY = 0


    def Set_verbosity_level():
        """Set the verbosity level.
        """

        def type_func(value):
            a_value = int(value)
            globals()['VERBOSITY'] = value
            print("Verbosity inside Set_verbosity_level(): " + str(globals()['VERBOSITY']))
            return value

        return type_func


    class CheckFile(argparse.FileType):
        """
        Check whatever in the file
        """

        def __init__(self,mode='r',**kwargs):
            super(CheckFile,self).__init__(mode,**kwargs)

        def __call__(self,string):
            # Do whatever processing/checking/transformation
            # e.g print some message according to verbosity
            print("Verbosity inside  CheckFile(): " + str(globals()['VERBOSITY']))
            return super(CheckFile,self).__call__(string)


    def make_parser():
        """The main argument parser."""
        parser = argparse.ArgumentParser(add_help=True)

        parser.add_argument("-V","--verbosity",default=0,type=Set_verbosity_level(),help="Increase output verbosity.",required=False)

        parser.add_argument('-i','--inputfile',help="Input file",type=CheckFile(mode='r'),required=True)

        return parser


    if __name__ == '__main__':
        myparser = make_parser()
        args = myparser.parse_args()
        print("Verbosity in Main: " + str(VERBOSITY))

调用此脚本将得到：

$python test.py -i test.bed -V 2
Verbosity inside  CheckFile(): 0
Verbosity inside Set_verbosity_level(): 2
Verbosity in Main: 2

最佳答案

我不知道您可以强制首先读取argparse变量,但可以在主要功能中使用命令行解析器中内置的python：

import sys

# Your classes here #

if __name__ == '__main__':
    verbosity = 0
    for i,sysarg in enumerate(sys.argv):
        if str(sysarg).strip().lower().replace('-','') in ['v','verbose']:
            try:
                verbosity = sys.argv[i + 1]
            except IndexError:
                print("No verbosity level specified")
    # more code

它不是很优雅,也不是argparse,但这是确保您首先获得详细信息的一种方法.

您还可以更新CheckFile类以包括详细检查功能：

class CheckFile(argparse.FileType):
    """
    Check whatever in the file
    """

    def __init__(self,**kwargs):
        super(CheckFile,**kwargs)

    def _check_verbosity(self):
        verbosity = 0
        for i,sysarg in enumerate(sys.argv):
            if str(sysarg).strip().lower().replace('-','verbose']:
                try:
                verbosity = sys.argv[i + 1]
            except IndexError:
                print("No verbosity level specified")

        return verbosity

    def __call__(self,string):
        # Do whatever processing/checking/transformation
        # e.g print some message according to verbosity
        print("Verbosity inside  CheckFile(): {}".format(self._check_verbosity()))
        return super(CheckFile,self).__call__(string)

同样,我知道这并不是您的argparse问题的真正答案,但这是您的问题的解决方案

原文链接：https://www.f2er.com/python/533265.html

有没有一种方法可以控制在Python argparse中评估参数的顺序

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