最佳答案
我自己用它:(我写的很快,因为它只是供个人使用).通过大量清理,您可以获得您想要的东西.见https://developers.google.com/chrome-developer-tools/docs/remote-debugging
原文链接：https://www.f2er.com/python/439326.htmlimport urllib2
import urllib
import os
import subprocess
import json
from websocket import create_connection
def refresh_page(url):
data = json.load(urllib2.urlopen('http://localhost:9222/json'))
found_page = False
for page in data:
if page['url'].lower() == url.lower():
found_page = True
websocketURL = page['webSocketDebuggerUrl']
ws = create_connection(websocketURL)
obj = { "id": 0,"method": "Page.reload","params":
{
"ignoreCache": True,"scriptToEvaluateOnLoad": ""
}
}
dev_request = json.dumps(obj)
ws.send(dev_request)
result = ws.recv()
ws.close()
if not found_page:
raise Exception("No pageFound")
def open_or_refresh(file_name):
file_name = "".join ( [f if f in r'\/:*?"<>|' else urllib.quote(f) for f in file_name] )
file_name = 'file:///' + file_name.replace('\\','/')
file_name = file_name.encode('ascii','ignore')
try:
refresh_page(file_name)
except:
cmd = (r'"%(LOCALAPPDATA)s\Google\Chrome\Application\chrome.exe"'%os.environ
+ r' --remote-debugging-port=9222 "%s"' % file_name)
subprocess.Popen(cmd)
open_or_refresh(r"C:\test.html")
open_or_refresh(r"C:\test.html")