[7,9,13,47,64,76,83,94,95,114,115,116,120,121,123,124,127,136,152,154,167,184,189,205,212,222,226,229,231,238]
这里连续的数字是(94,95),(120,121)和(123,124).
我该如何删除它们？
我的代码是：
while len(set(l)) != 30:
a = random.randint(1,240)
l.append(a)
l = list(set(l))
l = sorted(l)
f.write(str(l))
我不想使用randrange或随机模块中的选择.
最佳答案
创建一个随机数a并检查a和a 1是否不在集合中：
原文链接：https://www.f2er.com/python/438944.htmlimport random
l = set()
while len(l) != 30:
a = random.randint(1,240)
if not {a-1,a,a+1} & l: # set intersection: empty == False == no common numbers
l.add(a)
l = sorted(l) # sorted creates a sorted list from any iterable
print(l)
输出：
[5,12,40,55,59,62,73,82,84,89,93,109,125,141,165,168,187,196,202,204,210,215,218,231]
直接使用集合可以检查数字(±1)是否已经非常快速地成为随机数的一部分.
数独：
作为功能：
import random
def get_random_numbers_no_neighboring_elems(min_num,max_num,amount):
"""Generates amount random numbers in [min_num,..,max_num] that do not
include neighboring numbers."""
# this is far from exact - it is best to have about 5+ times the amount
# of numbers to choose from - if the margin is too small you might take
# very long to get all your "fitting numbers" as only about 1/4 of the range
# is a viable candidate (worst case):
# [1 2 3 4 5 6 7 8 9 10]: draw 2 then 5 then 8 and no more are possible
if (max_num-min_num) // 5 < amount:
raise ValueError(f"Range too small - increase given range.")
l = set()
while len(l) != amount:
a = random.randint(min_num,max_num)
if not {a-1,a+1} & l: # set intersection: empty == False == no commons
l.add(a)
return sorted(l)
print(get_random_numbers_no_neighboring_elems(1,240,80))