我检查了类似问题的其他解决方案,但是sqlite不支持row_number()和rank()函数,或者没有涉及连接多个表的示例,将它们按多列分组并且同时仅为每个组返回前N个结果.
这是我运行的代码
@H_404_7@db = sqlite3.connect('mydb')
cursor = db.cursor()
cursor.execute(
'''
CREATE TABLE orders(
id INTEGER PRIMARY KEY,product_id INTEGER,client_id INTEGER
)
'''
)
cursor.execute(
'''
CREATE TABLE clients(
id INTEGER PRIMARY KEY,gender TEXT,city TEXT
)
'''
)
cursor.execute(
'''
CREATE TABLE products(
id INTEGER PRIMARY KEY,category_name TEXT
)
'''
)
orders = [
(9,6),(3,10),(8,(4,8),(5,(7,4),(9,2),(10,1),7),9),(2,(6,3),(1,5),9)
]
clients = [
('Male','NY'),('Female',('Male','London'),'London')
]
products = [
('Kitchen',),('Sport',('Furniture',('Kitchen',)
]
cursor.executemany("INSERT INTO orders(product_id,client_id) VALUES(?,?)",orders)
cursor.executemany("INSERT INTO clients(gender,city) VALUES(?,clients)
cursor.executemany("INSERT INTO products(category_name) VALUES(?)",(products))
db.commit()
cursor.execute(
'''
SELECT
category_name,city,gender,product_id,COUNT(product_id)
FROM orders
LEFT JOIN products ON product_id = products.id
LEFT JOIN clients ON client_id = clients.id
GROUP BY product_id,category_name,gender
ORDER BY category_name,COUNT(product_id) DESC
'''
)
print('''category_name,COUNT(product_id)''')
all_rows = cursor.fetchall()
for a,b,c,d,e in all_rows:
print(a,e)
db.close()
现在的问题是如何在单个查询中获得这样的输出？我不需要与红线交叉的行,因为我只需要前2.
最佳答案
这可以通过使用WITH将现有查询嵌入CTE中,然后在WHERE … IN子查询中使用它来实现.子查询从CTE中选择与category_name,city和gender匹配的LIMIT 2产品ID,按产品计数排序.
@H_404_7@
WITH order_groups AS (
SELECT
category_name,COUNT(product_id) AS product_count
FROM orders OO
LEFT JOIN products ON product_id = products.id
LEFT JOIN clients ON client_id = clients.id
GROUP BY product_id,gender
ORDER BY category_name,COUNT(product_id) DESC
)
SELECT * FROM order_groups OG_outer
WHERE OG_outer.product_id IN (
SELECT product_id
FROM order_groups OG_inner
WHERE
OG_outer.category_name = OG_inner.category_name AND
OG_outer.city = OG_inner.city AND
OG_outer.gender = OG_inner.gender
ORDER BY OG_inner.product_count DESC LIMIT 2
)
ORDER BY category_name,product_count DESC
这将按要求输出以下行：
@H_404_7@Furniture|London|Female|4|2
Furniture|London|Female|3|1
Furniture|London|Male|4|3
Furniture|London|Male|3|2
Furniture|NY|Female|5|2
Furniture|NY|Female|4|1
Furniture|NY|Male|3|3
Furniture|NY|Male|4|1
Kitchen|London|Female|9|2
Kitchen|London|Female|8|1
Kitchen|London|Male|9|3
Kitchen|London|Male|8|1
Kitchen|NY|Female|9|4
Kitchen|NY|Female|10|2
Kitchen|NY|Male|1|1
Kitchen|NY|Male|8|1
Sport|London|Female|7|2
Sport|London|Female|2|1
Sport|London|Male|7|2
Sport|London|Male|6|1
Sport|NY|Female|2|2
Sport|NY|Female|6|2
Sport|NY|Male|7|3