如何阻止和等待基于回调的异步,Python函数调用

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我有一个Python脚本会产生许多异步请求.我正在使用的API进行回调.

函数调用run,我希望它阻止执行,直到所有请求都返回.

我可以在Python 2.7中使用什么来实现这一目标?

def run():
    for request in requests:
        client.send_request(request,callback)

def callback(error,response):
    # handle response
    pass

def main():
    run()

    # I want to block here
最佳答案
我发现最简单,侵入性最小的方法是使用threading.Event,available in 2.7.

import threading
import functools

def run():
    events = []
    for request in requests:
        event = threading.Event()
        callback_with_event = functools.partial(callback,event)
        client.send_request(request,callback_with_event)
        events.append(event)

    return events

def callback(event,error,response):
    # handle response
    event.set()

def wait_for_events(events):
    for event in events:
        event.wait()

def main():
    events = run()
    wait_for_events(events)
原文链接:https://www.f2er.com/python/438595.html

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