请多多包涵.我是Python的新手 – 但有很多乐趣.我正在尝试编写一个网络爬虫代码,用于搜索丹麦最后一次公投的选举结果.我设法从主页面中提取所有相关链接.现在我希望Python遵循92个链接中的每一个,并从每个页面中收集9条信息.但我很困惑.希望你能给我一个提示.
这是我的代码：
import requests
import urllib2
from bs4 import BeautifulSoup
# This is the original url http://www.kmdvalg.dk/
soup = BeautifulSoup(urllib2.urlopen('http://www.kmdvalg.dk/').read())
my_list = []
all_links = soup.find_all("a")
for link in all_links:
link2 = link["href"]
my_list.append(link2)
for i in my_list[1:93]:
print i
# The output shows all the links that I would like to follow and gather information from. How do I do that?
最佳答案
一个简单的方法是遍历您的URL列表并分别解析它们：
原文链接：https://www.f2er.com/python/438463.htmlfor url in my_list:
soup = BeautifulSoup(urllib2.urlopen(url).read())
# then parse each page individually here
from requests_futures.sessions import FuturesSession
def my_parse_function(html):
"""Use this function to parse each page"""
soup = BeautifulSoup(html)
all_paragraphs = soup.find_all('p')
return all_paragraphs
session = FuturesSession(max_workers=5)
futures = [session.get(url) for url in my_list]
page_results = [my_parse_function(future.result()) for future in results]