我正在使用numpy 1.9和最新版本的Theano编写此代码,但是我收到了一个我无法解决的错误.我怀疑它可能是我声明变量类型的方式,但我无法解决它.我感谢你的建议.我想用矢量生成矩阵,并用偏差求和.
import theano.tensor as T
from theano import function
import numpy as np
import pprint
def test_theano_matrix():
pp = pprint.PrettyPrinter(indent=3)
W= T.fmatrix()
x=T.fvector()
b= T.fvector()
y = T.dot(W,x) + b
lin_func = function([W,x,b],y)
dt = np.dtype(np.float)
w_inp = np.matrix('1 0;0 1',dtype=dt)
x_inp = np.matrix('2;1',dtype=dt)
b_inp = np.matrix('0;0',dtype=dt)
lin_func(w_inp,x_inp,b_inp)
if __name__ == '__main__':
test_theano_matrix()
我收到以下错误：
raise TypeError(err_msg,data)
TypeError: ('Bad input argument to theano function at index 0(0-based)','TensorType(float32,matrix) cannot store a value of dtype float64 without risking loss of precision. If you do not mind this loss,you can: 1) explicitly cast your data to float32,or 2) set "allow_input_downcast=True" when calling "function".',matrix([[ 1.,0.],[ 0.,1.]]))
谢谢你的时间！