我正在尝试编写一个剪贴板,但我遇到编码问题.当我试图将我正在寻找的字符串复制到我的文本文件中时,python2.7告诉我它没有识别编码,尽管没有特殊字符.不知道这是否有用.
我的代码看起来像这样：
from urllib import FancyURLopener
import os
class MyOpener(FancyURLopener): #spoofs a real browser on Window
version = 'Mozilla/5.0 (Windows; U; Windows NT 5.1; it; rv:1.8.1.11) Gecko/20071127 Firefox/2.0.0.11'
print "What is the webaddress?"
webaddress = raw_input("8::>")
print "Folder Name?"
foldername = raw_input("8::>")
if not os.path.exists(foldername):
os.makedirs(foldername)
def urlpuller(start,page):
while page[start]!= '"':
start += 1
close = start
while page[close]!='"':
close += 1
return page[start:close]
myopener = MyOpener()
response = myopener.open(webaddress)
site = response.read()
nexturl = ''
counter = 0
while(nexturl!=webaddress):
counter += 1
start = 0
for i in range(len(site)-35):
if site[i:i+35].decode('utf-8') == u'<img id="imgSized" class="slideImg"':
start = i + 40
break
else:
print "Something's broken,chief. Error = 1"
next = 0
for i in range(start,8,-1):
if site[i:i+8] == u'<a href=':
next = i
break
else:
print "Something's broken,chief. Error = 2"
nexturl = urlpuller(next,site)
myopener.retrieve(urlpuller(start,site),foldername+'/'+foldername+str(counter)+'.jpg')
print("Retrieval of "+foldername+" completed.")
当我尝试使用我正在使用的网站运行它时,它会返回错误：
Traceback (most recent call last):
File "yada/yadayada/Python/scraper.py",line 37,in <module>
if site[i:i+35].decode('utf-8') == u'<img id="imgSized" class="slideImg"':
File "/usr/lib/python2.7/encodings/utf_8.py",line 16,in decode
return codecs.utf_8_decode(input,errors,True)
UnicodeDecodeError: 'utf8' codec can't decode byte 0xc3 in position 34: unexpected end of data
当指向http://google.com时,它工作得很好.
<Meta http-equiv="Content-Type" content="text/html; charset=utf-8">
但是当我尝试使用utf-8进行解码时,正如您所看到的,它不起作用.
有什么建议？
解决方法
site[i:i+35].decode('utf-8')
您不能随机对您收到的字节进行分区,然后请UTF-8对其进行解码. UTF-8是一种多字节编码,这意味着您可以使用1到6个字节来表示一个字符.如果你把它切成两半,并要求Python解码它,它会让你意外结束数据错误.
查看为您构建的工具. BeautifulSoup或lxml是两种选择.