在Postgresql里,with子句提供了一种方法写一个大的查询中使用的辅助报表与查询。它有助于打破复杂和大型查询简单易读的形式。
1. 建表postgres=# create table tb9(id serial primary key,name character varying,parentid integer); CREATE TABLE
postgres=# \d tb9 Table "public.tb9" Column | Type | Modifiers ----------+-------------------+-------------------------------------------------- id | integer | not null default nextval('tb9_id_seq'::regclass) name | character varying | parentid | integer | Indexes: "tb9_pkey" PRIMARY KEY,btree (id)2. 插入测试数据
postgres=# insert into tb9 values(generate_series(1,5),'john',0); INSERT 0 5 postgres=# insert into tb9 values(6,'john1',1); INSERT 0 1 postgres=# insert into tb9 values(7,'john2',1); INSERT 0 1 postgres=# insert into tb9 values(8,'john11',6); INSERT 0 1
postgres=# select * from tb9; id | name | parentid ----+--------+---------- 1 | john | 0 2 | john | 0 3 | john | 0 4 | john | 0 5 | john | 0 6 | john1 | 1 7 | john2 | 1 8 | john11 | 6 (8 rows)3. with子句
postgres=# with t as (select * from tb9 where parentid=1) select count(0) from t; count ------- 2 (1 row)
postgres=# with t(a,b,c) as (select * from tb9 where parentid=1) select a,c from t; a | b | c ---+-------+--- 6 | john1 | 1 7 | john2 | 1 (2 rows)4. 多个with子句的结合使用
parentid=1的记录的所有子记录
postgres=# with t1 as (select * from tb9),t2 as(select * from tb9 where parentid=1) select t1.* from t1,t2 where t2.id=t1.parentid; id | name | parentid ----+--------+---------- 8 | john11 | 6 (1 row)5. 递归
id为1的记录的所有子记录
postgres=# with recursive t as(select id,name,parentid from tb9 where id=1 union all select k.id,k.name,k.parentid from tb9 k,t where t.id=k.parentid) select * from t; id | name | parentid ----+--------+---------- 1 | john | 0 6 | john1 | 1 7 | john2 | 1 8 | john11 | 6 9 | john21 | 7 (5 rows)