1. 建表
postgres=# create table tb1(id integer,name character varying);
CREATE TABLE postgres=# postgres=# insert into tb1 select generate_series(1,5),'aa';
INSERT 0 5
2. 返回单字段的多行(returns setof datatype)
- 不指定out参数,使用return next xx:
create or replace function func01()returns setof character varying as $$ declare n character varying;
begin for i in 1..5 loop select name into n from tb1 where id=i;
return next n;
end loop;
end $$ language plpgsql;
- 指定out参数,使用return next:
create or replace function func02(out character varying)returns setof character varying as $$ begin for i in 1..5 loop select name into $1from tb1 where id=i;
return next;
end loop;
end $$ language plpgsql;
- 使用return query:
create or replace function func03()returns setof character varying as $$ begin for i in 1..5 loop return query(select name from tb1 where id=i);
end loop;
end $$language plpgsql;
3. 返回多列的多行(returns setog record)
- 不指定out参数,使用return next xx:
create or replace function func04()RETURNS SETOF RECORD as $$ declare r record;
begin for i in 1..5 loop select * into r from tb1 where id=i;
return next r;
end loop;
end;
$$language plpgsql;
在使用func04的时候注意,碰到问题列下:
问题一:
postgres=# select func04();
ERROR: set-valued function called in context that cannot accept a set
CONTEXT: PL/pgsql function func04() line 7 at RETURN NEXT
解决:(来自: https://wiki.postgresql.org/wiki/Return_more_than_one_row_of_data_from_PL/pgSQL_functions)
If you call your set-returning function the wrong way (IOW the way you might normally call a function),you will get this error message: Set-valued function called in context that cannot accept a set. Incorrect: select sr_func(arg1,arg2,…); Correct: select * from sr_func(arg1,…);
问题二:
postgres=# select * from func04();
ERROR: a column definition list is required for functions returning "record"
LINE 1: select * from func04();
解决: (来自: http://stackoverflow.com/questions/8605174/postgresql-error-42601-a-column-definition-list-is-required-for-functions-ret
http://francs3.blog.163.com/blog/static/4057672720125232216773/)
postgres=# select * from func04() as t(id integer,name character varying);
id | name ----+------
1 | aa
2 | aa
3 | aa
4 | aa
5 | aa
(5 rows)
这个问题在func04如果指定out参数就不会有问题,如下func05所示:
- 指定out参数,使用return next:
create or replace function func05(out out_id integer,out out_name character varying)returns setof record as $$ declare r record;
begin for i in 1..5 loop select * into r from tb1 where id=i;
out_id:=r.id;
out_name:=r.name;
return next;
end loop;
end;
$$language plpgsql;
postgres=# select * from func05();
id | name ----+------
1 | aa
2 | aa
3 | aa
4 | aa
5 | aa
(5 rows)
- 使用return query:
create or replace function func06()returns setof record as $$ begin for i in 1..5 loop return query(select id,name from tb1 where id=i);
end loop;
end;
$$language plpgsql;
postgres=# select * from func06() as t(id integer,name character varying);
id | name ----+------
1 | aa
2 | aa
3 | aa
4 | aa
5 | aa
(5 rows)