我有一张表示亲子关系的表.关系可以深入n级.
我已经使用以下查询创建了一个示例表:
CREATE SEQUENCE relations_rel_id_seq INCREMENT BY 1 NO MAXVALUE NO MINVALUE CACHE 1; CREATE TABLE relations( rel_id bigint DEFAULT nextval('relations_rel_id_seq'::regclass) NOT NULL PRIMARY KEY,rel_name text,rel_display text,rel_parent bigint );
我需要查询表并分层显示父子关系.我仍然不了解如何使用SQL查询查询n级深度.
rel1 rel11 rel111 rel112 rel1121 rel2 rel21 rel211 rel212
N.B:n级中的值n是未知的.
数据库设计:
Is there any better way such a relation can be expressed in the
database for easy querying.?
使用Postgres可以使用递归公用表表达式:
with recursive rel_tree as ( select rel_id,rel_name,rel_parent,1 as level,array[rel_id] as path_info from relations where rel_parent is null union all select c.rel_id,rpad(' ',p.level * 2) || c.rel_name,c.rel_parent,p.level + 1,p.path_info||c.rel_id from relations c join rel_tree p on c.rel_parent = p.rel_id ) select rel_id,rel_name from rel_tree order by path_info;
基于您的示例sqlFiddle:http://sqlfiddle.com/#!11/59319/19