我需要确定在我的数据库中为某些物化视图授予的特权.
为表或标准视图执行此操作的查询非常简单:
SELECT grantee,string_agg(privilege_type,',') AS privileges FROM information_schema.table_privileges WHERE table_schema = 'some_schema' AND table_name = 'some_table' GROUP by grantee;
也就是说,物化视图似乎不是一个类似的表格. Postgresql在哪里存储这些信息?
Postgres
system catalogs是有关安装和数据库的完整信息的基本信息.
Information schema作为辅助功能是基于系统目录,并提供与其他RDBM的兼容性.
系统目录是最可靠的信息来源.
原文链接:https://www.f2er.com/postgresql/191787.htmlInformation schema作为辅助功能是基于系统目录,并提供与其他RDBM的兼容性.
系统目录是最可靠的信息来源.
您可以将information_schema.table_privileges视为基于pg_class和pg_roles的特定视图.
显然,在执行中必须有一个小错误(这是在正确的地方缺少一个字母的问题).
系统目录pg_class包含关于列relacl中所有权限的所有信息.
如果列为空,则所有者具有所有权限.
在acl字符串中用作用户名的空字符串表示公开.
create materialized view test_view as select 1; grant select on test_view to public; grant delete on test_view to a_user; select coalesce(nullif(s[1],''),'public') as grantee,s[2] as privileges from pg_class c join pg_namespace n on n.oid = relnamespace join pg_roles r on r.oid = relowner,unnest(coalesce(relacl::text[],format('{%s=arwdDxt/%s}',rolname,rolname)::text[])) acl,regexp_split_to_array(acl,'=|/') s where nspname = 'public' and relname = 'test_view'; grantee | privileges ----------+------------ postgres | arwdDxt public | r a_user | d (3 rows)
create or replace function priviliges_from_acl(text) returns text language sql as $$ select string_agg(privilege,') from ( select case ch when 'r' then 'SELECT' when 'w' then 'UPDATE' when 'a' then 'INSERT' when 'd' then 'DELETE' when 'D' then 'TRUNCATE' when 'x' then 'REFERENCES' when 't' then 'TRIGGER' end privilege from regexp_split_to_table($1,'') ch ) s $$;
使用:
select coalesce(nullif(s[1],priviliges_from_acl(s[2]) as privileges from pg_class c join pg_namespace n on n.oid = relnamespace join pg_roles r on r.oid = relowner,'=|/') s where nspname = 'public' and relname = 'test_view'; grantee | privileges ----------+--------------------------------------------------------------- postgres | INSERT,SELECT,UPDATE,DELETE,TRUNCATE,REFERENCES,TRIGGER public | SELECT a_user | DELETE (3 rows)