如何在SQLAlchemy和postgresql中结合两个子查询

原始sql需要：

SELECT
    id
FROM
   (SELECT some_table.id FROM some_table WHERE some_table.some_field IS NULL) AS subq1
   UNION
   (SELECT some_table.id WHERE some_table.some_field IS NOT NULL)
LIMIT 10;

这是python代码：

import sqlalchemy

SOME_TABLE = sqlalchemy.Table(
 'some_table',sqlalchemy.MetaData(),sqlalchemy.Column('id',sqlalchemy.Integer,primary_key=True),sqlalchemy.Column('some_field',sqlalchemy.Text))

stmt_1 = sqlalchemy.sql.select(SOME_TABLE.columns).where(SOME_TABLE.columns.some_field != None)
stmt_2 = sqlalchemy.sql.select(SOME_TABLE.columns).where(SOME_TABLE.columns.some_field == None)

# This gets a programming error.
stmt_1.union(stmt_2).limit(10);

这是输出的sql(带有参数交换),它会收到此错误：
错误：“UNION”处或附近的语法错误：

SELECT some_table.id,some_table.some_field
FROM some_table
WHERE some_table.some_field IS NOT NULL
 LIMIT 10 UNION SELECT some_table.id,some_table.some_field
FROM some_table
WHERE some_table.some_field IS NULL
 LIMIT 10
 LIMIT 10

我如何为子查询添加别名？

我用了一点点不同的方法：

# the first subquery,select all ids from SOME_TABLE where some_field is not NULL
s1 = select([SOME_TABLE.c.id]).where(SOME_TABLE.c.some_field != None)

# the second subquery,select all ids from SOME_TABLE where some_field is NULL
s2 = select([SOME_TABLE.c.id]).where(SOME_TABLE.c.some_field != None)

# union s1 and s2 subqueries together and alias the result as "alias_name"
q = s1.union(s2).alias('alias_name')

# run the query and limit the aliased result to 10
session.query(q).limit(10)

这是生成的sql：

SELECT alias_name.id AS alias_name_id 
FROM (SELECT some_table.id AS id 
FROM some_table 
WHERE some_table.some_field IS NOT NULL UNION SELECT some_table.id AS id 
FROM some_table 
WHERE some_table.some_field IS NULL) AS alias_name 
LIMIT 10

我想这就是你想要的结果.

原文链接：https://www.f2er.com/postgresql/191677.html

如何在SQLAlchemy和postgresql中结合两个子查询

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