oracle – 如何在PL / SQL中对关联数组进行排序?

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@H_502_0@
@H_502_0@
我有一个像这样的关联数组:

continent_population('Australia') := 30;
continent_population('Antarctica') := 90;
continent_population('UK') := 50;

如何在PL / sql中的值之后对此数组进行排序?谢谢!

解决方法

您不能按值对关联数组进行排序,但您必须将数据转换为其他数据结构并在那里进行排序.最简单的方法是转换到另一个关联数组,其中键和值交换位置,但这要求您的键值也应该是唯一的.

以下是从Sorting PL/SQL Collections开始适用于您的案例的示例.请查看该文章了解详细信息.

/* The sorting is done with sql thus these types have to be sql types. */

create type sortable_t is object(
  continent varchar2(32767),population number
);
/

create type sortable_table_t is table of sortable_t;
/

declare
  type continent_population_t is table of pls_integer index by varchar2(32767);
  continent_population continent_population_t;

  i varchar2(32767);

  sorted sortable_table_t := sortable_table_t();
begin
  /* Populate original data. */

  continent_population('Australia') := 30;
  continent_population('Antarctica') := 90;
  continent_population('UK') := 50;
  continent_population('USA') := 50;

  /* Convert to a helper data type that is used for sorting. */

  i := continent_population.first;

  while i is not null loop
    sorted.extend(1);
    sorted(sorted.last) := new sortable_t(i,continent_population(i));
    i := continent_population.next(i);
  end loop;

  /* Show that the content is not sorted yet. */

  dbms_output.put_line('Unsorted:');
  for j in sorted.first .. sorted.last loop
    dbms_output.put_line(sorted(j).continent || ' = ' || sorted(j).population);
  end loop;

  /* Sorting with sql. */

  select cast(multiset(select *
                       from table(sorted)
                       order by 2 asc,1 asc)
              as sortable_table_t)
    into sorted
    from dual;

  /* Show that the content is now sorted. */

  dbms_output.put_line('Sorted by value:');
  for j in sorted.first .. sorted.last loop
    dbms_output.put_line(sorted(j).continent || ' = ' || sorted(j).population);
  end loop;

end;
/

打印:

Unsorted:
Antarctica = 90
Australia = 30
UK = 50
USA = 50
Sorted by value:
Australia = 30
UK = 50
USA = 50
Antarctica = 90
@H_502_0@

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