UTL_LMS.FORMAT_MESSAGE调用VARCHAR参数,但doc(11gR2)示例中的类型转换似乎与整数变量兼容.但是,我的%d永远不会被替换.
我希望得到一些想法/建议.下面是失败的一个例子.
运行以下内容:
DECLARE C_INTRANSITIVE_VERB CONSTANT VARCHAR2(50) := 'breakdance'; C_SUBJECT_NOUN CONSTANT VARCHAR2(50) := 'hobbit'; C_PREPOSITION_OBJECT CONSTANT VARCHAR2(50) := 'wookie'; C_MULTIPLIER CONSTANT INTEGER := 19; C_TEMPLATE CONSTANT VARCHAR2(400) := 'The %s likes to %s with the %s %d times a day.'; BEGIN DBMS_OUTPUT.PUT_LINE('My integer is: '|| C_MULTIPLIER); DBMS_OUTPUT.PUT_LINE( UTL_LMS.FORMAT_MESSAGE(C_TEMPLATE,C_SUBJECT_NOUN,C_INTRANSITIVE_VERB,C_PREPOSITION_OBJECT,C_MULTIPLIER) ); END; /
产量:
My integer is: 19
The hobbit likes to breakdance with the wookie times a day.
但是,下面转换raw int fine:
DECLARE C_INTRANSITIVE_VERB CONSTANT VARCHAR2(50) := 'breakdance'; C_SUBJECT_NOUN CONSTANT VARCHAR2(50) := 'hobbit'; C_PREPOSITION_OBJECT CONSTANT VARCHAR2(50) := 'wookie'; C_MULTIPLIER CONSTANT INTEGER := 19; C_TEMPLATE CONSTANT VARCHAR2(400) := 'The %s likes to %s with the %s %d times a day.'; BEGIN DBMS_OUTPUT.PUT_LINE('My integer is: '|| C_MULTIPLIER); DBMS_OUTPUT.PUT_LINE( UTL_LMS.FORMAT_MESSAGE(C_TEMPLATE,19) ); END; /
My integer is: 19
The hobbit likes to breakdance with the wookie 19 times a day.
以下解决方法是不合需要的.
DECLARE C_INTRANSITIVE_VERB CONSTANT VARCHAR2(50) := 'breakdance'; C_SUBJECT_NOUN CONSTANT VARCHAR2(50) := 'hobbit'; C_PREPOSITION_OBJECT CONSTANT VARCHAR2(50) := 'wookie'; C_MULTIPLIER CONSTANT INTEGER := 19; C_TEMPLATE CONSTANT VARCHAR2(400) := 'The %s likes to %s with the %s %d times a day.'; BEGIN DBMS_OUTPUT.PUT_LINE('My integer is: '|| C_MULTIPLIER); DBMS_OUTPUT.PUT_LINE( UTL_LMS.FORMAT_MESSAGE(C_TEMPLATE,TO_CHAR(C_MULTIPLIER)) ); END; /
My integer is: 19
The hobbit likes to breakdance with the wookie 19 times a day.
>为什么FORMAT_MESSAGE接受原始整数,但在INTEGER类型(或一般NUMBER类型)变量上失败?
>是否有更好的预包装(11g)dbms消息格式化器已经可用?
> oracle 11g中有关清除消息格式的任何其他建议吗?我会考虑包装java的MessageFormat / String #format(),或者创建一个处理char类型转换的FORMAT_MESSAGE委托,但更愿意为所有需要它的数据库避免这种情况,而且我不太热衷于“只记得“to_char()到处都是因为失败相当安静.
谢谢!
https://docs.oracle.com/database/121/ARPLS/u_lms.htm#ARPLS71196
该示例指定PLS_INTEGER而不是Integer或Number.我已经测试了这个,并且使用PLS_INTEGER可以在Integer没有的情况下工作.
我知道这不是一个理想的解决方案,我不确定是否定义您的变量,因为pls_integer将是一个选项.但可能会有一些帮助.
DECLARE C_INTRANSITIVE_VERB CONSTANT VARCHAR2(50) := 'breakdance'; C_SUBJECT_NOUN CONSTANT VARCHAR2(50) := 'hobbit'; C_PREPOSITION_OBJECT CONSTANT VARCHAR2(50) := 'wookie'; C_MULTIPLIER CONSTANT PLS_INTEGER := 19; C_TEMPLATE CONSTANT VARCHAR2(400) := 'The %s likes to %s with the %s %d times a day.'; BEGIN DBMS_OUTPUT.PUT_LINE('My integer is: '|| C_MULTIPLIER); DBMS_OUTPUT.PUT_LINE( UTL_LMS.FORMAT_MESSAGE(C_TEMPLATE,C_MULTIPLIER) ); END;
给出输出
My integer is: 19 The hobbit likes to breakdance with the wookie 19 times a day.