Oracle的行列转换

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转自:http://blog.csdn.net/xb12369/article/details/39554935


尝试sql: 统计每天每个类型操作个用多少用户

select *
from (select trunc(created_time),action_type,user_id
from t_shq_task_operate_log l
where l.created_time > trunc(sysdate - 7)
and l.created_time < trunc(sysdate)
and l.action_type in (0,1,2,3,4)) pivot(count(distinct user_id) for action_type in (0,4));


首先感谢提供Oracle的行列转换丝路!!!


原始表数据:



辅助思考:

  1. selectusertelephone,
  2. max(decode(filedid,answervalue,0))as"问题1",
  3. max(decode(filedid,0))as"问题2",0))as"问题3",4,0))as"问题4",5,0))as"问题5",6,0))as"问题6",7,0))as"问题7"
  4. fromt_d_Serveyanswerwhereserveyid=3groupbyusertelephoneorderby1asc;




涨姿势的关键字:pivot




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存储过程实现动态行转列:http://www.cnblogs.com/QQParadise/articles/1712093.html

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原文链接:https://www.f2er.com/oracle/211780.html

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