1. select * from emp;
2. select empno,ename,job from emp;
3. select empno 编号,ename 姓名,job 工作 from emp;
4. select job from emp;
5. select distinct job from emp;
6. select distinct empno,job from emp;
说明:因为雇员编号不重复,所以此时证明所有的列没有重复,所以不能消除掉重复的列.
7. 查询出雇员的编号,姓名,工作,但是显示的格式:编号是: 7369 的雇员,姓名是: smith,工作是: clear
select '编号是: ' || empno || '的雇员,姓名是: ' || ename || ',工作是: ' || job from emp;
8. 求出每个雇员的姓名及年薪
select ename,sal * 12 income from emp;
9. 求出工资大于 1500 的所有雇员信息
select * from emp where sal > 1500;
10. 查询每月可以得到奖金的雇员信息
select * from emp where comm is not null;
11. 查询没有奖金的雇员信息
select * from emp where comm is null;
12. 查询出基本工资大于 1500 同时可以领取奖金的雇员信息
select * from emp where sal > 1500 and comm is not null;
13. 查询出基本工资大于 1500 或者可以领取奖金的雇员信息
select * from emp where sal > 1500 or comm is not null;
14. 查询出基本工资不大于 1500 或者不可以领取奖金的雇员信息
select * from emp where not(sal > 1500 and comm is not null);
15. 查询基本工资大于 1500,但是小于 3000 的全部雇员信息
select * from emp where sal > 1500 and sal < 3000;
16. 查询基本工资大于等于 1500,但是小于等于 3000 的全部雇员信息
select * from emp where sal >= 1500 and sal <= 3000;
select * from emp where sal between 1500 and 3000;
17. 查询出在 1981 年雇佣的全部雇员信息(1981 年 1 月 1 日 到 1981 年 12 月 31 日之间的雇佣的雇员)
select * from emp where hiredate between '1-1月-81' and '31-12月-81';
18. 要求查询出姓名是 smith 的雇员信息
select * from emp where ename = 'SMITH';
19. 要求查询出雇员是 7369,7499,7521 的雇员的具体信息
select * from emp where empno = 7369 or empno = 7499 or empno = 7521;
select * from emp where empno in(7369,7521);
20. 要求查询出雇员不是 7369,7521 的雇员的具体信息
select * from emp where empno not in(7369,宋体; line-height:25.2px"> 21. 要求查询出姓名是 smith,allen,king 的雇员信息
select * from emp where ename in('SMITH','ALLEN','KING');
22. 查询出所有雇员姓名中第二个字母包含 "M" 的雇员信息
select * from emp where ename like '_M%';
23. 查询出雇员姓名中包含字母 M 的雇员信息
select * from emp where ename like '%M%';
24. 要求查询出在 1981 年雇佣的雇员信息
select * from emp where hiredate like '%81%';
25. 查询工资中包含 5 的雇员信息
select * from emp where sal like '%5%';
26. 查询雇员编号不是 7369 的雇员信息
select * from emp where empno != 7369;
select * from emp where empno <> 7369;
27. 要求按照工资由低到高排序
select * frm emp order by sal;
select * from emp order by sal asc;
28. 要求按照工资由高到低排序
select * from emp order by sal desc;
29. 要求查询出 20 部门的所有雇员信息,查询的信息按照工资由高到低排序,如果工资相等,则按照雇佣日期由早到晚排序.
select * from emp where deptno = 20 order by sal desc,hiredate asc;
30. 将小写字母变为大写字母
select upper('hello') from dual;
31. 将大写字母变为小写字母
select lower('HELLO WORLD') from dual;
32. 要求查询出姓名是 smith 的雇员信息
select * from emp where ename = upper('smith');
33. 使用 initcap() 函数将单词的第一个字母大写
select initcap('hello world') from dual;
34. 将雇员表中的雇员姓名变为开头字母大写
select initcap(ename) from emp;
35. 将字符串 "hello" 和 "world" 进行串联
select concat('hello ','world') from dual;
36. 对字符串进行操作的常用字符处理函数
select substr('hello',1,3) 截取字符串,length('hello') 字符串的长度,replace('hello','l','x') 字符串替换 from dual;
select substr('hello','x') 字符串替换 from dual;
37. 显示所有雇员的姓名及姓名的后三个字符
select ename,substr(ename,length(ename) -2) from emp;
select ename,-3,3) from emp;
38. 使用数值函数执行四舍五入操作
select round(789.536) from dual;
39. 要求将 789.536 数值保留两位小数
select round(789.536,2) from dual;
40. 要求将 789.536 数值中的整数的十位进行四舍五入进位
select round(789.536,-2) from dual;
41. 采用 trunc() 函数不会保留任何小数,而且小数点也不会执行四舍五入的操作
select trunc(789.536) from dual;
42. 通过 trunc() 也可以指定小数点的保留位数
select trunc(789.536,宋体; line-height:25.2px"> 43. 作用负数表示位数
select trunc(789.536,宋体; line-height:25.2px"> 44. 使用 mod() 函数可以进行取余的操作
select mod(10,3) from dual;
45. 显示 10 部门雇员进入公司的星期数(当前日期 - 雇佣日期 = 天数 / 7 = 星期数)
select empno,round((sysdate - hiredate) / 7) from emp where deptno = 10;
46. 日期函数
months_between(): 求出给定日期范围的月数
add_months(): 在指定的日期上加上指定的月数,求出之后的日期
next_day(): 指定日期的下一个日期
last_day(): 求出给定日期当月的最后一天日期
47.
select empno,months_between(sysdate,hiredate) from emp;
select empno,round(months_between(sysdate,hiredate)) from emp;
48. select sysdate,add_months(sysdate,4) from dual;
49. select next_day(sysdate,'星期一') from dual;
50. select last_day(sysdate) from dual;
51. 转换函数
to_char(): 转换成字符串
to_number(): 转换成数字
to_date(): 转换成日期
52. 查询所有雇员的雇员编号,雇佣日期
select empno,
ename,
to_char(hiredate,'yyyy') year,'mm') months,'dd') day
from emp;
select empno,to_char(hiredate,'yyyy-mm-dd') from emp;
53. 查询所有雇员的编号,姓名和工资
select empno,sal from emp;
select empno,to_char(sal,'99,999') from emp;
select empno,'L99,'$99,999') from emp;
54. select to_number('123') + to_number('123') from dual;
55. 将一个字符串转换成日期类型
select to_date('2009-01-01','yyyy-mm-dd') from dual;
56. 求出每个雇员的年薪(要求加上奖金)
select empno,sal,comm,(sal + comm) * 12 from emp;
select empno,nvl(comm,0),(sal + nvl(comm,0)) * 12 income from emp;
57. decode() 函数类似于 if....elsif...else 语句
select decode(1,'内容是 1',2,'内容是 2',3,'内容是 3') from dual;
58. 查询出雇员的编号,雇佣日期及工作,要求将雇员的工作替换成以下信息:
select empno 雇员编号,
ename 雇员姓名,
hiredate 雇佣日期,
decode(job,
'CLERK','业务员',
'SALESMAN','销售人员',
'MANAGER','经理',
'ANALYST','分析员',
'PRESIDENT','总裁'
) 职位
from emp;
59. 笛卡尔积(交差连接)
select * from emp,dept;
select * from emp cross join dept;
60. 内连接
select * from emp e,dept d where e.deptno = d.deptno;
select * from emp e inner join dept d on e.deptno = d.deptno;
select * from emp e join dept d on e.deptno = d.deptno;
61. 自然连接
select * from emp natural join dept;
select * from emp e join dept d using(deptno);
62. 要求查询出雇员的编号,部门的编号,名称,地址
select e.empno,e.ename,d.deptno,d.dname,d.loc from emp e,dept d where e.deptno = d.deptno;
63. 要求查询出雇员的姓名,雇员的直接上级领导姓名
select e.ename,e.job,m.ename from emp e,emp m where e.mgr = m.empno;
64. 要求查询出雇员的姓名,雇员的直接上级领导姓名以及部门名称
select e.ename,m.ename,d.dname from emp e,emp m,dept d where e.mgr = m.empno and e.deptno = d.deptno;
65. 要求查询出每个雇员的姓名,工资,部门名称,工资在公司的等级(salgrade),及其领导的姓名及工资所在公司的等级
select e.ename,e.sal,s.grade,m.sal,ms.grade
from emp e,dept d,salgrade s,salgrade ms
where e.deptno = d.deptno
and e.sal between s.losal and s.hisal
and e.mgr = m.empno
and m.sal between ms.losal and ms.hisal;
select e.ename,
e.sal,
d.dname,
decode(s.grade,'第五等级','第四等级','第三等级',4,'第二等级',5,'第一等级'),
m.ename,
m.sal,
decode(ms.grade,'第一等级')
from emp e,salgrade ms
where e.deptno = d.deptno and e.sal between s.losal and s.hisal and e.mgr = m.empno
and m.sal between ms.losal and ms.hisal;
66. select empno,dname,loc from emp e,dept d where e.deptno = d.deptno;
select empno,loc from emp e inner join dept d on e.deptno = d.deptno;
67. 左外连接
select empno,dept d where e.deptno = d.deptno(+);
select empno,loc from emp e left outer join dept d on e.deptno = d.deptno;
select empno,loc from emp e left join dept d on e.deptno = d.deptno(+);
68. 右外连接
select empno,dept d where e.deptno(+) = d.deptno;
select empno,loc from emp e right outer join dept d on e.deptno = d.deptno;
select empno,loc from emp e right join dept d on e.deptno = d.deptno;
69. select e.empno,m.empno,宋体; line-height:25.2px"> 70. select e.empno,emp m where e.mgr = m.empno(+);
71.
select * from emp e,dept d where e.deptno = d.deptno and d.deptno = 30;
select * from emp e inner join dept d on e.deptno = d.deptno where d.deptno = 30;
select * from emp e join dept d on e.deptno = d.deptno where d.deptno = 30;
select * from emp e natural join dept d where deptno = 30;
select * from emp e join dept d using(deptno) where deptno = 30;
72.
select e.ename,d.loc from emp e right outer join dept d on e.deptno = d.deptno;
select e.ename,d.loc from emp e right join dept d on e.deptno = d.deptno;
select e.ename,dept d where e.deptno(+) = d.deptno;
73. select count(ename) from emp;
74. select min(sal) from emp;
75. select max(sal) from emp;
76. select sum(sal) from emp;
77. select avg(sal) from emp;
78. select sum(sal) from emp where deptno = 20;
79. select avg(sal) from emp where deptno = 20;
80. 求出每个部门的雇员数量
select deptno,count(deptno) from emp group by deptno; select deptno,count(empno) from emp group by deptno;
81. 求出每个部门的平均工资
select deptno,avg(sal) from emp group by deptno;
select d.dname,count(e.empno) from emp e,dept d where e.deptno = d.deptno group by d.dname; select d.deptno,temp.c from (select deptno,count(e.empno) c from emp e group by e.deptno) temp,dept d where temp.deptno = d.deptno;
83. 要求显示出平均工资大于 2000 的部门编号和平均工资
select deptno,avg(sal) from emp group by deptno having avg(sal) > 2000;
84. 显示非销售人员工作名称以及从事同一工作雇员的月工资的总和,并且要满足从事同一工作的雇员的月工资合计大于 5000,输出结果按月工资的合计升序排序.
select job,sum(sal) su from emp where job <> 'SALESMAN' group by job having sum(sal) > 5000 order by su; select temp.job,sum(temp.sal) s from (select job,sal from emp e where job <> 'SALESMAN') temp group by temp.job having sum(temp.sal) > 5000 order by s;
85. 求出平均工资最高的部门工资
86. 要求查询出比雇员编号为 7654 工资高的所有雇员信息
select * from emp where sal >(select sal from emp where empno = 7654);
87. 要求查询出工资比 7654 高,同时与 7788 从事相同工作的全部雇员信息
select * from emp where sal >(select sal from emp where empno = 7654) and job = (select job from emp where empno = 7788);
88. 要求查询出工资最低的雇员姓名,工资
select ename,job,sal from emp where sal = (select min(sal) from emp);
89. 要求查询出: 部门名称，部门的员工数，部门的平均工资，部门的最低收入雇员的姓名
select d.dname,temp.c,temp.a,e.ename from dept d,(select deptno,count(empno) c,avg(sal) a,min(sal) m from emp group by deptno) temp,emp e where d.deptno = temp.deptno and e.sal = temp.m; select d.deptno,temp.dname,e.sal from (select d.dname,count(e.empno) c,avg(e.sal) a,min(e.sal) m from emp e,dept d where e.deptno = d.deptno group by d.dname) temp,emp e,dept d where temp.m = e.sal and temp.dname = d.dname;
90. 求出每个部门的最低工资的雇员的信息
select * from emp where sal in(select min(sal) from emp group by deptno); select * from emp where sal =any(select min(sal) from emp group by deptno); select * from (select min(sal) m from emp group by deptno) temp,emp e where e.sal = temp.m;
91. 范例 90 中,比子查询条件中最低(小)的工资要大的雇员信息
select * from emp where sal >any(select min(sal) from emp group by deptno); select * from emp where sal > (select min(min(sal)) from emp group by deptno);
92. 范例 90 中,比子查询条件中最高(大)的工资要小的雇员信息
select * from emp where sal <any(select min(sal) from emp group by deptno); select * from emp where sal < (select max(min(sal)) from emp group by deptno);
93. 范例 90 中,比子查询条件中最高(大)的工资要大的雇员信息
select * from emp where sal >all(select min(sal) from emp group by deptno); select * from emp where sal > (select max(min(sal)) from emp group by deptno);
94. 范例 90 中,比子查询条件中最低(小)的工资要小的雇员信息
select * from emp where sal <all(select min(sal) from emp group by deptno); select * from emp where sal < (select min(min(sal)) from emp group by deptno);
95. 查找出 20 部门中没有奖金的雇员信息
select * from emp where (sal,-1)) in (select sal,-1) from emp where deptno = 20); select * from emp where deptno = 20 and comm is null;
96. union 操作符返回两个查询选定的所有不重复的行
select deptno from emp union select deptno from dept;
97. union all 操作符合并两个查询选定的所有行，包括重复的行
select deptno from emp union all select deptno from dept;
98. intersect 操作符只返回两个查询都有的行
select deptno from emp intersect select deptno from dept;
99. minus 操作符只返回由第一个查询选定但是没有被第二个查询选定的行,也就是在第一个查询结果中排除在第二个查询结果中出现的行
select deptno from dept minus select deptno from emp;
