我写了一个简单的程序.我尝试将选择结果存储在变量中.我使用“SELECT INTO”查询,但我不能这样做.
例：
DECLARE
v_employeeRecord employee%ROWTYPE;
BEGIN
SELECT * INTO v_employeeRecord
FROM Employee WHERE Salary > 10;
END;
你有几个选择.您可以将该查询转换为游标：
原文链接：https://www.f2er.com/oracle/205089.htmlDECLARE
CURSOR v_employeeRecords IS
SELECT * FROM Employee WHERE Salary > 10;
v_employeeRecord employee%ROWTYPE;
BEGIN
FOR v_employeeRecord IN v_employeeRecords LOOP
/* Do something with v_employeeRecord */
END LOOP;
END;
或者,您可以创建一个TABLE变量：
DECLARE
v_employeeRecord employee%ROWTYPE;
v_employeeRecords IS TABLE OF employee%ROWTYPE;
i BINARY_INTEGER;
BEGIN
SELECT * BULK COLLECT INTO v_employeeRecords
FROM Employee WHERE Salary > 10;
i := v_employeeRecords.FIRST;
WHILE v_employeeRecords.EXISTS(i) LOOP
v_employeeRecord := v_employeeRecords(i);
/* Do something with v_employeeRecord */
i := v_employeeRecords.NEXT(i);
END;
END;
我没有在Oracle中尝试这些示例,因此您可能会遇到编译器错误…
