我正在学习使用sinon的节点模块mockery进行单元测试.
仅使用mockery和普通类我能够成功注入模拟.但是我想注入一个sinon存根而不是一个简单的类,但是我遇到了很多麻烦.
我试图嘲笑的课程：
function LdapAuth(options) {}
// The function that I want to mock.
LdapAuth.prototype.authenticate = function (username,password,callback) {}
beforeEach(function() {
ldapAuthMock = sinon.stub(LdapAuth.prototype,"authenticate",function(username,callback) {});
mockery.registerMock('ldapauth-fork',ldapAuthMock);
mockery.enable();
});
afterEach(function () {
ldapAuthMock.restore();
mockery.disable();
});
我试图以各种方式模拟/存根LdapAuth类但没有成功,上面的代码只是最新版本无效.
所以我只想知道如何使用sinon和mockery成功地模拟这个.
解决方法
由于Node的模块缓存,Javascript的动态特性以及它的原型继承,这些节点模拟库可能非常麻烦.
幸运的是,Sinon还负责修改你试图模拟的对象,并提供一个很好的API来构建spys,subs和mocks.
这是一个关于如何存根authenticate方法的小例子：
// ldap-auth.js
function LdapAuth(options) {
}
LdapAuth.prototype.authenticate = function (username,callback) {
callback(null,'original');
}
module.exports = LdapAuth;
// test.js
var sinon = require('sinon');
var assert = require('assert');
var LdapAuth = require('./ldap-auth');
describe('LdapAuth#authenticate(..)',function () {
beforeEach(function() {
this.authenticateStub = sinon
// Replace the authenticate function
.stub(LdapAuth.prototype,'authenticate')
// Make it invoke the callback with (null,'stub')
.yields(null,'stub');
});
it('should invoke the stubbed function',function (done) {
var ldap = new LdapAuth();
ldap.authenticate('user','pass',function (error,value) {
assert.ifError(error);
// Make sure the "returned" value is from our stub function
assert.equal(value,'stub');
// Call done because we are testing an asynchronous function
done();
});
// You can also use some of Sinon's functions to verify that the stub was in fact invoked
assert(this.authenticateStub.calledWith('user','pass'));
});
afterEach(function () {
this.authenticateStub.restore();
});
});
我希望这有帮助.
